题目内容
| 1 |
| 2 |
| 2 |
| 5 |
25
25
%,| 2 |
| 5 |
| 1 |
| 2 |
20
20
%.分析:先求出
与
的差,用差除以
就是
时比
时多百分之几;用差除以
就是
时比
时少百分之几.
| 2 |
| 5 |
| 1 |
| 2 |
| 2 |
| 5 |
| 1 |
| 2 |
| 2 |
| 5 |
| 1 |
| 2 |
| 2 |
| 5 |
| 1 |
| 2 |
解答:解:(
-
)÷
=0.1÷0.4
=25%
(
-
)÷
=0.1÷0.5
=20%
答:
时比
时多25%,
时比
时少20%.
故答案为:25,20.
| 1 |
| 2 |
| 2 |
| 5 |
| 2 |
| 5 |
=0.1÷0.4
=25%
(
| 1 |
| 2 |
| 2 |
| 5 |
| 1 |
| 2 |
=0.1÷0.5
=20%
答:
| 1 |
| 2 |
| 2 |
| 5 |
| 2 |
| 5 |
| 1 |
| 2 |
故答案为:25,20.
点评:本题关键是确定谁是单位“1”,解答依据是:求一个数是另一个数的百分之几,用除法计算.
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