题目内容
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分析:(1)依据等式的性质,方程两边同时加
,再同时除以
求解;
(2)先化简方程,再依据等式的性质,方程两边同时除以
求解;
(3)先化简方程,再依据等式的性质,方程两边同时减
,最后同时除以
求解.
| 3 |
| 4 |
| 3 |
| 5 |
(2)先化简方程,再依据等式的性质,方程两边同时除以
| 5 |
| 6 |
(3)先化简方程,再依据等式的性质,方程两边同时减
| 1 |
| 2 |
| 7 |
| 8 |
解答:解:(1)
X-
=
,
X-
+
=
+
,
X÷
=1÷
,
x=1
;
(2)
X+
X=3,
x=3,
x÷
=3÷
,
x=3
;
(3)
X+
=
×8,
X+
-
=4-
,
X=3
,
X÷
=3
÷
,
x=4.
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| 5 |
| 3 |
| 4 |
| 1 |
| 4 |
| 3 |
| 5 |
| 3 |
| 4 |
| 3 |
| 4 |
| 1 |
| 4 |
| 3 |
| 4 |
| 3 |
| 5 |
| 3 |
| 5 |
| 3 |
| 5 |
x=1
| 2 |
| 3 |
(2)
| 1 |
| 2 |
| 1 |
| 3 |
| 5 |
| 6 |
| 5 |
| 6 |
| 5 |
| 6 |
| 5 |
| 6 |
x=3
| 3 |
| 5 |
(3)
| 7 |
| 8 |
| 1 |
| 2 |
| 1 |
| 2 |
| 7 |
| 8 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 7 |
| 8 |
| 1 |
| 2 |
| 7 |
| 8 |
| 7 |
| 8 |
| 1 |
| 2 |
| 7 |
| 8 |
x=4.
点评:本题主要考查学生依据等式的性质解方程的能力,解方程时注意对齐等号.
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