题目内容
直接写出得数:
16.15÷1.7+0.85÷1.7=
199+99×99=
+
-
+
-
=
6
+4
+5.375+3
=
10.1×99-9.9=
3×32+
+
+
=
16.15÷1.7+0.85÷1.7=
10
10
199+99×99=
10000
10000
| 1 |
| 2 |
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| 37 |
| 60 |
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6
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20
20
10.1×99-9.9=
990
990
3×32+
| 9 |
| 10 |
| 9 |
| 100 |
| 9 |
| 1000 |
27.999
27.999
.分析:(1)根据乘法分配律的变形进行简算;
(2)先把第二个99化成100-1,然后运用乘法分配律简算,再运用加法结合律简算;
(3)运用加法结合律简算;
(4)运用加法结合律简算;
(5)先把10.1×99化成101×9.9然后再运用乘法分配律简算;
(6)32表示3×3,先算出乘法,再把分数化成小数再计算.
(2)先把第二个99化成100-1,然后运用乘法分配律简算,再运用加法结合律简算;
(3)运用加法结合律简算;
(4)运用加法结合律简算;
(5)先把10.1×99化成101×9.9然后再运用乘法分配律简算;
(6)32表示3×3,先算出乘法,再把分数化成小数再计算.
解答:解:(1)16.15÷1.7+0.85÷1.7,
=(16.15+0.85)÷1.7,
=17÷1.7,
=10;
(2)199+99×99,
=199+99×(100-1),
=199+99×100-99,
=199+9900-99,
=9900+(199-99),
=9900+100,
=10000;
(3)
+
-
+
-
,
=(
-
)+(
-
)+
,
=
+
+
,
=
+
,
=
;
(4)6
+4
+5.375+3
,
=(6
+3
)+(4
+5
),
=10+10,
=20;
(5)10.1×99-9.9,
=101×9.9-9.9,
=(101-1)×9.9,
=100×9.9,
=990;
(6)3×32+
+
+
,
=3×9+
+
+
,
=27+0.9+0.09+0.009,
=27.999.
故答案为:10,10000,
,20,990,27.999
=(16.15+0.85)÷1.7,
=17÷1.7,
=10;
(2)199+99×99,
=199+99×(100-1),
=199+99×100-99,
=199+9900-99,
=9900+(199-99),
=9900+100,
=10000;
(3)
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| 3 |
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| 5 |
| 1 |
| 6 |
=(
| 1 |
| 2 |
| 1 |
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| 1 |
| 3 |
| 1 |
| 6 |
| 1 |
| 5 |
=
| 1 |
| 4 |
| 1 |
| 6 |
| 1 |
| 5 |
=
| 5 |
| 12 |
| 1 |
| 5 |
=
| 37 |
| 60 |
(4)6
| 1 |
| 3 |
| 5 |
| 8 |
| 2 |
| 3 |
=(6
| 1 |
| 3 |
| 2 |
| 3 |
| 5 |
| 8 |
| 3 |
| 8 |
=10+10,
=20;
(5)10.1×99-9.9,
=101×9.9-9.9,
=(101-1)×9.9,
=100×9.9,
=990;
(6)3×32+
| 9 |
| 10 |
| 9 |
| 100 |
| 9 |
| 1000 |
=3×9+
| 9 |
| 10 |
| 9 |
| 100 |
| 9 |
| 1000 |
=27+0.9+0.09+0.009,
=27.999.
故答案为:10,10000,
| 37 |
| 60 |
点评:本题考查了稍复杂的四则混合运算,要仔细观察算式的特点,灵活运用一些定律进行简便计算.
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