题目内容
脱式计算
5400-2940÷28×27
(20.2×40%+7.88)÷4.2
(
+
)÷
+
10÷[2.6-(
÷
+
)].
5400-2940÷28×27
(20.2×40%+7.88)÷4.2
(
| 4 |
| 5 |
| 1 |
| 4 |
| 7 |
| 3 |
| 7 |
| 10 |
10÷[2.6-(
| 5 |
| 13 |
| 5 |
| 26 |
| 2 |
| 5 |
分析:(1)先算除法和乘法,再算减法;
(2)把百分数化为小数,先算括号内的乘法,再算括号内的加法,最后算括号外的除法;
(3)先算括号内的加法,再算括号外的除法,最后算括号外的加法;
(4)先算小括号内的除法,再算小括号内的加法,然后算中括号内的减法,最后算括号外的除法.
(2)把百分数化为小数,先算括号内的乘法,再算括号内的加法,最后算括号外的除法;
(3)先算括号内的加法,再算括号外的除法,最后算括号外的加法;
(4)先算小括号内的除法,再算小括号内的加法,然后算中括号内的减法,最后算括号外的除法.
解答:解:(1)5400-2940÷28×27
=5400-105×27
=5400-2835
=2565;
(2)(20.2×40%+7.88)÷4.2
=(20.2×0.4+7.88)÷4.2
=(8.08+7.88)÷4.2
=15.96÷4.2
=3.8;
(3)(
+
)÷
+
=
×
+
=
+
=
;
(4)10÷[2.6-(
÷
+
)]
=10÷[2.6-(
×
+
)]
=10÷[2.6-(2+0.4)]
=10÷[2.6-2.4]
=10÷0.2
=50.
=5400-105×27
=5400-2835
=2565;
(2)(20.2×40%+7.88)÷4.2
=(20.2×0.4+7.88)÷4.2
=(8.08+7.88)÷4.2
=15.96÷4.2
=3.8;
(3)(
| 4 |
| 5 |
| 1 |
| 4 |
| 7 |
| 3 |
| 7 |
| 10 |
=
| 21 |
| 20 |
| 3 |
| 7 |
| 7 |
| 10 |
=
| 9 |
| 20 |
| 7 |
| 10 |
=
| 23 |
| 20 |
(4)10÷[2.6-(
| 5 |
| 13 |
| 5 |
| 26 |
| 2 |
| 5 |
=10÷[2.6-(
| 5 |
| 13 |
| 26 |
| 5 |
| 2 |
| 5 |
=10÷[2.6-(2+0.4)]
=10÷[2.6-2.4]
=10÷0.2
=50.
点评:此题考查了四则混合运算,注意运算顺序和运算法则以及数字转化.
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