题目内容
| 计算下面各题能简算的要简算 5.02-1.37-2.63 |
1.8×
|
1.25×2.5×32 | ||||||||||||
(27+
|
|
|
分析:(1)可根据一个数减两个数,等于用这个数减去这两个数的和的减法性质计算.
(2)可将式中分数化成百分数后,根据乘法分配律计算.
(3)可将32变为8×4后根据乘法交换律与结合律计算.
(4)可将除法算式变为乘法算式后,根据乘法分配律计算.
(5)可将式中分数与百分数化成小数后,根据乘法分配律计算.
(6)先算括号中的乘法,再算加法,最后算除法.
(2)可将式中分数化成百分数后,根据乘法分配律计算.
(3)可将32变为8×4后根据乘法交换律与结合律计算.
(4)可将除法算式变为乘法算式后,根据乘法分配律计算.
(5)可将式中分数与百分数化成小数后,根据乘法分配律计算.
(6)先算括号中的乘法,再算加法,最后算除法.
解答:解:(1)5.02-1.37-2.63
=5.02-(1.37+2.63)
=5.02-4
=1.02;
(2)1.8×
+2.2×25%
=1.8×25%+2.2×25%
=(1.8+2.2)×25%
=4×25%
=1;
(3)1.25×2.5×32
=1.25×8×(4×2.5)
=10×10
=100;
(4)(27+
)÷9
=(27+
)×
=27×
+
×
=3+
=3
;
(5)
×3.5+5.5×80%+0.8
=0.8×3.5+5.5×0.8+0.8
=0.8×(5.5+3.5+1)
=0.8×10
=8;
(6)
÷(
+
×
)
=
÷(
+
)
=
÷
=
.
=5.02-(1.37+2.63)
=5.02-4
=1.02;
(2)1.8×
| 1 |
| 4 |
=1.8×25%+2.2×25%
=(1.8+2.2)×25%
=4×25%
=1;
(3)1.25×2.5×32
=1.25×8×(4×2.5)
=10×10
=100;
(4)(27+
| 18 |
| 19 |
=(27+
| 18 |
| 19 |
| 1 |
| 9 |
=27×
| 1 |
| 9 |
| 18 |
| 19 |
| 1 |
| 9 |
=3+
| 2 |
| 19 |
=3
| 2 |
| 19 |
(5)
| 4 |
| 5 |
=0.8×3.5+5.5×0.8+0.8
=0.8×(5.5+3.5+1)
=0.8×10
=8;
(6)
| 13 |
| 18 |
| 5 |
| 6 |
| 2 |
| 3 |
| 3 |
| 8 |
=
| 13 |
| 18 |
| 5 |
| 6 |
| 1 |
| 4 |
=
| 13 |
| 18 |
| 13 |
| 12 |
=
| 2 |
| 3 |
点评:完成本题要注意分析式中数据的特点,然后运用合适的方法计算.
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