题目内容
计算:101
+1001
+10001
=
| 1 |
| 2 |
| 3 |
| 4 |
| 7 |
| 8 |
11105
| 1 |
| 8 |
11105
.| 1 |
| 8 |
分析:原式可化成101
+1001
+10001
=101+
+1001+
+10001+
=(101+1001+10001)+(
+
+
)进行计算即可.
| 1 |
| 2 |
| 3 |
| 4 |
| 7 |
| 8 |
| 1 |
| 2 |
| 3 |
| 4 |
| 7 |
| 8 |
| 1 |
| 2 |
| 3 |
| 4 |
| 7 |
| 8 |
解答:解:101
+1001
+10001
,
=101+
+1001+
+10001+
,
=(101+1001+10001)+(
+
+
),
=11103+
,
=11105
.
| 1 |
| 2 |
| 3 |
| 4 |
| 7 |
| 8 |
=101+
| 1 |
| 2 |
| 3 |
| 4 |
| 7 |
| 8 |
=(101+1001+10001)+(
| 1 |
| 2 |
| 3 |
| 4 |
| 7 |
| 8 |
=11103+
| 17 |
| 8 |
=11105
| 1 |
| 8 |
点评:此题考查了分数的加法运算,灵活计算即可.
练习册系列答案
相关题目