题目内容
0.325×0.465+0.535×1.2+0.465×0.675= ．
分析：本题根据加法交换律及连续运用乘法分配律计算即可．
解答：解：0.325×0.465+0.535×1.2+0.465×0.675
=0.325×0.465+0.465×0.675+0.535×1.2
=（0.325+0.675）×0.465+0.535×1.2
=1×0.465+0.535×（1+0.2）
=1×0.465+0.535×1+0.535×0.2
=（0.465+0.535）×1+0.535×0.2
=1×1+0.107
=1.107．
故答案为：1.107．
=0.325×0.465+0.465×0.675+0.535×1.2
=（0.325+0.675）×0.465+0.535×1.2
=1×0.465+0.535×（1+0.2）
=1×0.465+0.535×1+0.535×0.2
=（0.465+0.535）×1+0.535×0.2
=1×1+0.107
=1.107．
故答案为：1.107．
点评：完成本题要注意分析式中数的据的特点，然后运用合适的方法计算．
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