题目内容
用适当的方法计算
[4-(
-
)]×
13×
-
63÷14
(
+
×
)÷
.
[4-(
| 3 |
| 4 |
| 1 |
| 8 |
| 4 |
| 29 |
13×
| 5 |
| 6 |
| 5 |
| 6 |
63÷14
(
| 4 |
| 9 |
| 2 |
| 3 |
| 5 |
| 6 |
| 6 |
| 7 |
考点:分数的四则混合运算
专题:运算顺序及法则
分析:(1)按照先算小括号里面的,再算中括号里面的,最后算括号外面的顺序计算解答,
(2)运用乘法分配律解答,
(3)化14=7×2,再运用除法性质解答,
(4)按照先算括号里面的乘法,再算括号里面的加法,最后算括号外面的顺序计算解答.
(2)运用乘法分配律解答,
(3)化14=7×2,再运用除法性质解答,
(4)按照先算括号里面的乘法,再算括号里面的加法,最后算括号外面的顺序计算解答.
解答:
解:(1)[4-(
-
)]×
=[4-
]×
=
×
=
;
(2)13×
-
=(13-1)×
=12×
=10;
(3)63÷14
=63÷(7×2)
=63÷7÷2
=9÷2
=4.5;
(4)(
+
×
)÷
=(
+
)÷
=1÷
=1
.
| 3 |
| 4 |
| 1 |
| 8 |
| 4 |
| 29 |
=[4-
| 5 |
| 8 |
| 4 |
| 29 |
=
| 27 |
| 8 |
| 4 |
| 29 |
=
| 27 |
| 58 |
(2)13×
| 5 |
| 6 |
| 5 |
| 6 |
=(13-1)×
| 5 |
| 6 |
=12×
| 5 |
| 6 |
=10;
(3)63÷14
=63÷(7×2)
=63÷7÷2
=9÷2
=4.5;
(4)(
| 4 |
| 9 |
| 2 |
| 3 |
| 5 |
| 6 |
| 6 |
| 7 |
=(
| 4 |
| 9 |
| 5 |
| 9 |
| 6 |
| 7 |
=1÷
| 6 |
| 7 |
=1
| 1 |
| 6 |
点评:本题主要考查学生依据四则运算计算方法正确进行计算,以及正确运用简便方法解决问题的能力.
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