题目内容
解方程.
20%χ-
=
χ+
χ=1
.
20%χ-
| 1 |
| 5 |
| 4 |
| 5 |
| 1 |
| 4 |
| 1 |
| 3 |
| 1 |
| 6 |
分析:(1)根据等式的性质,在方程两边同时加上
,再除以0.2求解,
(2)先化简,再根据等式的性质,在方程两边同时乘上
求解,
| 1 |
| 5 |
(2)先化简,再根据等式的性质,在方程两边同时乘上
| 12 |
| 7 |
解答:解:(1)20%x-
=
,
20%x-
+
=
+
,
0.2x÷0.2=1÷0.2,
x=5;
(2)
x+
x=1
,
x=1
,
x×
=
×
,
x=2.
| 1 |
| 5 |
| 4 |
| 5 |
20%x-
| 1 |
| 5 |
| 1 |
| 5 |
| 4 |
| 5 |
| 1 |
| 5 |
0.2x÷0.2=1÷0.2,
x=5;
(2)
| 1 |
| 4 |
| 1 |
| 3 |
| 1 |
| 6 |
| 7 |
| 12 |
| 1 |
| 6 |
| 7 |
| 12 |
| 12 |
| 7 |
| 7 |
| 6 |
| 12 |
| 7 |
x=2.
点评:本题考查了学生根据等式的性质解方程的能力,注意等号对齐.
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