题目内容
3.计算.| $\frac{1}{48}$÷($\frac{1}{6}$+$\frac{3}{4}$) | $\frac{3}{4}$÷$\frac{2}{3}$×$\frac{3}{2}$ | 52$\frac{4}{13}$÷$\frac{13}{17}$ |
| 33-$\frac{7}{22}$×11 | 12×$\frac{3}{4}$×$\frac{2}{3}$ | $\frac{6}{13}$×2$\frac{1}{6}$×3 |
| 48-$\frac{2}{3}$-$\frac{3}{4}$ | $\frac{3}{5}$÷$\frac{3}{11}$÷4 | (1$\frac{2}{9}$-$\frac{7}{12}$)×1$\frac{7}{23}$÷$\frac{5}{6}$. |
分析 (1)(2)根据分数的四则混合运算顺序计算即可;
(3)把52$\frac{4}{13}$化为52+$\frac{4}{13}$,再根据乘法分配律进行计算;
(4)先算乘法,再算减法即可;
(5)(6)根据分数的乘法运算约分即可;
(7)从左到右相减即可;
(8)先把除法转化为乘法,再计算即可;
(9)先算括号里的减法,再算乘除即可.
解答 解:(1)$\frac{1}{48}$÷($\frac{1}{6}$+$\frac{3}{4}$)
=$\frac{1}{48}$÷$\frac{11}{12}$
=$\frac{1}{44}$;
(2)$\frac{3}{4}$÷$\frac{2}{3}$×$\frac{3}{2}$
=$\frac{3}{4}$×$\frac{3}{2}$×$\frac{3}{2}$
=$\frac{27}{16}$;
(3)52$\frac{4}{13}$÷$\frac{13}{17}$
=(52+$\frac{4}{13}$)÷$\frac{13}{17}$
=52÷$\frac{13}{17}$+$\frac{4}{13}$÷$\frac{13}{17}$
=68+$\frac{68}{169}$
=$68\frac{68}{169}$;
(4)33-$\frac{7}{22}$×11
=33-$\frac{7}{2}$
=$29\frac{1}{2}$;
(5)12×$\frac{3}{4}$×$\frac{2}{3}$
=9×$\frac{2}{3}$
=6;
(6)$\frac{6}{13}$×2$\frac{1}{6}$×3
=$\frac{6}{13}$×$\frac{13}{6}$×3
=3;
(7)48-$\frac{2}{3}$-$\frac{3}{4}$
=$47\frac{1}{3}-\frac{3}{4}$
=$46\frac{7}{12}$;
(8)$\frac{3}{5}$÷$\frac{3}{11}$÷4
=$\frac{3}{5}$×$\frac{11}{3}$×$\frac{1}{4}$
=$\frac{11}{20}$;
(9)(1$\frac{2}{9}$-$\frac{7}{12}$)×1$\frac{7}{23}$÷$\frac{5}{6}$
=$\frac{23}{36}$×$\frac{30}{23}$×$\frac{6}{5}$
=1.
点评 本题考查了分数的四则混合运算,完成本题要注意分析式中数据,运用合适的简便方法计算.
| 18×5= | 64÷16= | 630÷21= | 120+80×3= |
| 20×500= | 20×19= | 210×40= | 25×24×4= |