题目内容
0.
125×0.
24
（x-4）×
=
x-
1-
-
+
-
+
-
．
| ||
| 983个0 |
| ||
| 1028个0 |
（x-4）×
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 6 |
1-
| 1 |
| 3 |
| 7 |
| 12 |
| 9 |
| 20 |
| 11 |
| 30 |
| 13 |
| 42 |
| 15 |
| 56 |
（1）由于0.125×1.24=0.03，
所以0.
125×0.
24积的小数点后有983+1028+1=2012个零，
则0.
125×0.
24=0.000…（2012个0）3．
（2）（x-4）×
=
x-
-
=
x-
，
-
-
+
=
-
+
-
，
=
，
×12=
×12，
x=14．
（3）1-
-
+
-
+
-
．
=1-
-（
+
）+（
+
）-（
+
）+（
+
）-（
+
），
=1-
-
-
+
+
-
-
+
+
-
-
，
=1-
-
-
，
=
-
，
=
．
所以0.
| ||
| 983个0 |
| ||
| 1028个0 |
则0.
| ||
| 983个0 |
| ||
| 1028个0 |
（2）（x-4）×
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 6 |
| x |
| 3 |
| 4 |
| 3 |
| 1 |
| 4 |
| 1 |
| 6 |
| x |
| 3 |
| x |
| 4 |
| 4 |
| 3 |
| 4 |
| 3 |
| x |
| 4 |
| x |
| 4 |
| 4 |
| 3 |
| 1 |
| 6 |
| x |
| 12 |
| 7 |
| 6 |
| x |
| 12 |
| 7 |
| 6 |
x=14．
（3）1-
| 1 |
| 3 |
| 7 |
| 12 |
| 9 |
| 20 |
| 11 |
| 30 |
| 13 |
| 42 |
| 15 |
| 56 |
=1-
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 6 |
| 1 |
| 6 |
| 1 |
| 7 |
| 1 |
| 7 |
| 1 |
| 8 |
=1-
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 5 |
| 1 |
| 6 |
| 1 |
| 6 |
| 1 |
| 7 |
| 1 |
| 7 |
| 1 |
| 8 |
=1-
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 8 |
=
| 1 |
| 3 |
| 1 |
| 8 |
=
| 5 |
| 24 |
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