题目内容
计算题:
①5÷4+5.6×125%+
÷
②
×(5-
÷4)+
③2×(x+7)-3.6=20.8
④
=4.5:5.4.
①5÷4+5.6×125%+
| 5 |
| 4 |
| 5 |
| 17 |
②
| 52 |
| 5 |
| 60 |
| 13 |
| 57 |
| 13 |
③2×(x+7)-3.6=20.8
④
| X-1 |
| 12 |
分析:算式①②根据乘法分配律计算即可.
算式③根据等式的性质解方程即可:等式的两边加上,减去,乘以,除以相同的数,等式仍然成立;
算式④根据比例的基本性质:比例的两外项之积等于两内项之积.以及等式的性质解比例即可.
算式③根据等式的性质解方程即可:等式的两边加上,减去,乘以,除以相同的数,等式仍然成立;
算式④根据比例的基本性质:比例的两外项之积等于两内项之积.以及等式的性质解比例即可.
解答:解:①5÷4+5.6×125%+
÷
=1.25+5.6×1.25+1.25×3.4,
=1.25×(1+5.6+3.4),
=1.25×10,
=12.5.
②
×(5-
÷4)+
=
×(5-
)+
,
=
×5-
×
+
,
=52-12+
,
=40+1
,
=41
;
③2×(x+7)-3.6=20.8
2x+14-3.6=20.8,
2x+10.4=20.8,
2x+10.4-10.4=20.8-10.4,
2x=10.4,
2x÷2=10.4÷2,
x=5.2.
④
=4.5:5.4
5.4(x-1)=12×4.5,
5.4x-5.4=54,
5.4x-5.4+5.4=54+5.4,
5.4x=59.4,
5.4x÷5.4=59.4÷5.4,
x=11.
| 5 |
| 4 |
| 5 |
| 17 |
=1.25+5.6×1.25+1.25×3.4,
=1.25×(1+5.6+3.4),
=1.25×10,
=12.5.
②
| 52 |
| 5 |
| 60 |
| 13 |
| 57 |
| 13 |
=
| 52 |
| 5 |
| 15 |
| 13 |
| 57 |
| 13 |
=
| 52 |
| 5 |
| 52 |
| 5 |
| 15 |
| 13 |
| 17 |
| 13 |
=52-12+
| 17 |
| 13 |
=40+1
| 4 |
| 13 |
=41
| 4 |
| 13 |
③2×(x+7)-3.6=20.8
2x+14-3.6=20.8,
2x+10.4=20.8,
2x+10.4-10.4=20.8-10.4,
2x=10.4,
2x÷2=10.4÷2,
x=5.2.
④
| X-1 |
| 12 |
5.4(x-1)=12×4.5,
5.4x-5.4=54,
5.4x-5.4+5.4=54+5.4,
5.4x=59.4,
5.4x÷5.4=59.4÷5.4,
x=11.
点评:当算式中同时含有分数、小数或百分数时,要根据式中数据的特点灵活将它们互化后再进行计算.
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