题目内容
计算:
+
+
+
+…+
+
.
| 1 |
| 1×2 |
| 1 |
| 2×3 |
| 1 |
| 3×4 |
| 1 |
| 4×5 |
| 1 |
| 998×999 |
| 1 |
| 999×1000 |
考点:分数的巧算
专题:计算问题(巧算速算)
分析:仔细观察每个加数,都是形如
的分数,而
=
-
,因此,要先将原式中各加数变形后再计算.
| 1 |
| n(n+1) |
| 1 |
| n(n+1) |
| 1 |
| n |
| 1 |
| n+1 |
解答:
解:
+
+
+
+…+
+
=1-
+
-
+
-
+
-
+
-
+
-
=1-
=
| 1 |
| 1×2 |
| 1 |
| 2×3 |
| 1 |
| 3×4 |
| 1 |
| 4×5 |
| 1 |
| 998×999 |
| 1 |
| 999×1000 |
=1-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 5 |
| 1 |
| 998 |
| 1 |
| 999 |
| 1 |
| 999 |
| 1 |
| 1000 |
=1-
| 1 |
| 1000 |
=
| 999 |
| 1000 |
点评:形如
的分数,都可以拆成两个分数相减的形式,然后通过加减相互抵消,求出结果.
| 1 |
| n(n+1) |
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