题目内容

用合理的方法计算:
(1)
2
3
+
1
3
×
3
4

(2)
2005
2006
×2007

(3)(
5
8
+
1
27
)×8+
19
27

(4)
3
5
×
1
7
+
8
21
÷
2
3

(5)
1
6
÷
[1÷(
3
5
-
3
10
)].
(1)
2
3
+
1
3
×
3
4

=
2
3
+
1
4

=
8
12
+
3
12

=
11
12

(2)
2005
2006
×2007

=
2005
2006
×
(2006+1),
=
2005
2006
×
2006+
2005
2006

=2005+
2005
2006

=2005
2005
2006

(3)(
5
8
+
1
27
)×8+
19
27

=
5
8
×
8+
1
27
×
8+
19
27

=5+(
8
27
+
19
27
),
=5+1,
=6;
(4)
3
5
×
1
7
+
8
21
÷
2
3
),
=
3
5
×(
1
7
+
8
21
×
3
2
),
=
3
5
×(
1
7
+
4
7
),
=
3
5
×
5
7

=
3
7

(5)
1
6
÷
[1÷(
3
5
-
3
10
)],
=
1
6
÷[1÷(
6
10
-
3
10
)],
=
1
6
÷[1÷
3
10
],
=
1
6
÷
10
3

=
1
6
×
3
10

=
1
20
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