题目内容
(2013?宜丰县模拟)计算下面各题,怎样简便就怎样算.
1.65÷5+1.29×0.2+
×20%
(
+
)×3+
×[
-(
-
)]
24×(
-
)÷
.
1.65÷5+1.29×0.2+
| 3 |
| 50 |
(
| 2 |
| 15 |
| 1 |
| 12 |
| 3 |
| 5 |
| 4 |
| 9 |
| 3 |
| 4 |
| 7 |
| 16 |
| 1 |
| 4 |
24×(
| 3 |
| 8 |
| 1 |
| 6 |
| 1 |
| 5 |
分析:(1)把题中的分数化为小数,再把1.65÷5化为1.65×0.2,运用乘法分配律解答,
(2)先运用乘法分配律,再运用加法交换律解答,
(3)运用减法的性质解答,
(4)运用乘法分配律解答.
(2)先运用乘法分配律,再运用加法交换律解答,
(3)运用减法的性质解答,
(4)运用乘法分配律解答.
解答:解:(1)1.65÷5+1.29×0.2+
×20%,
=1.65×0.2+1.29×0.2+0.06×0.2,
=(1.65+1.29+0.06)×0.2,
=3×0.2,
=0.6;
(2)(
+
)×3+
,
=
+
+
,
=1+
,
=1
;
(3)
×[
-(
-
)],
=
×[
+
-
],
=
×[1-
],
=
×
,
=
;
(4)24×(
-
)÷
,
=[24×
-24×
]÷
,
=[9-4]÷
,
=5÷
,
=25.
| 3 |
| 50 |
=1.65×0.2+1.29×0.2+0.06×0.2,
=(1.65+1.29+0.06)×0.2,
=3×0.2,
=0.6;
(2)(
| 2 |
| 15 |
| 1 |
| 12 |
| 3 |
| 5 |
=
| 2 |
| 5 |
| 1 |
| 4 |
| 3 |
| 5 |
=1+
| 1 |
| 4 |
=1
| 1 |
| 4 |
(3)
| 4 |
| 9 |
| 3 |
| 4 |
| 7 |
| 16 |
| 1 |
| 4 |
=
| 4 |
| 9 |
| 3 |
| 4 |
| 1 |
| 4 |
| 7 |
| 16 |
=
| 4 |
| 9 |
| 7 |
| 16 |
=
| 4 |
| 9 |
| 9 |
| 16 |
=
| 1 |
| 4 |
(4)24×(
| 3 |
| 8 |
| 1 |
| 6 |
| 1 |
| 5 |
=[24×
| 3 |
| 8 |
| 1 |
| 6 |
| 1 |
| 5 |
=[9-4]÷
| 1 |
| 5 |
=5÷
| 1 |
| 5 |
=25.
点评:本题主要考查了学生运用四则运算简便算法解决问题的能力.
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