题目内容
解方程.
(1)4x+2(8-x)=36
(2)
x=
×
.
(1)4x+2(8-x)=36
(2)
| 8 |
| 9 |
| 1 |
| 6 |
| 16 |
| 51 |
分析:(1)根据题意,先计算2(8-x)=16-2x,再计算4x-2x=2x,等式的两边同时减去16,然后等式的两边再同时除以2即可;
(2)等式的两边同时除以
即可.
(2)等式的两边同时除以
| 8 |
| 9 |
解答:解:(1)4x+2(8-x)=36,
4x+16-2x=36,
2x+16=36,
2x+16-16=36-16,
2x=20,
2x÷2=20÷2,
x=10;
(2)
x=
×
,
x÷
=
×
÷
,
x=
×
×
,
x=
.
4x+16-2x=36,
2x+16=36,
2x+16-16=36-16,
2x=20,
2x÷2=20÷2,
x=10;
(2)
| 8 |
| 9 |
| 1 |
| 6 |
| 16 |
| 51 |
| 8 |
| 9 |
| 8 |
| 9 |
| 1 |
| 6 |
| 16 |
| 51 |
| 8 |
| 9 |
x=
| 1 |
| 6 |
| 16 |
| 51 |
| 9 |
| 8 |
x=
| 1 |
| 17 |
点评:本题主要考查解方程,根据等式的性质进行解答即可.
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