题目内容
脱式计算(能简便的要简便计算)
|
|
4.2×102-8.4 | ||||||||||||||
|
3.64÷4+4.36×25% | 1110÷[56×(
| ||||||||||||||
36-
|
|
分析:(1)先算小括号里面的加法,再算中括号里面的除法,再算括号外的除法;
(2)先把除法变成乘法,然后利用乘法分配律简算;
(3)先把8.4分解成4.2×2,再利用乘法分配律简算;
(4)先算小括号里面的减法,再算括号外的除法,最后算乘法;
(5)先把除法变成乘法,25%化成分数,再利用乘法分配律简算;
(6)先把中括号里面的运算用乘法分配律简算,再算括号外的除法.
(7)先把方程两边同时加上
X,使X前边的运算为加法;然后再根据等式的性质解方程;
(8)本题是已知比的前项和比值,求比的后项;根据比的性质,用比的前项除以比值就是比的后项.
(2)先把除法变成乘法,然后利用乘法分配律简算;
(3)先把8.4分解成4.2×2,再利用乘法分配律简算;
(4)先算小括号里面的减法,再算括号外的除法,最后算乘法;
(5)先把除法变成乘法,25%化成分数,再利用乘法分配律简算;
(6)先把中括号里面的运算用乘法分配律简算,再算括号外的除法.
(7)先把方程两边同时加上
| 2 |
| 3 |
(8)本题是已知比的前项和比值,求比的后项;根据比的性质,用比的前项除以比值就是比的后项.
解答:解:(1)
÷[(
+
)÷
],
=
÷[
÷
],
=
÷
,
=
;
(2)
×
+
÷4,
=
×
+
×
,
=
×(
+
),
=
×1,
=
;
(3)4.2×102-8.4,
=4.2×102-4.2×2,
=4.2×(102-2),
=4.2×100,
=420;
(4)
÷(1-
)×
,
=
÷
×
,
=
×
,
=
;
(5)3.64÷4+4.36×25%,
=3.64×
+4.36×
,
=(3.64+4.36)×
,
=8×
,
=2;
(6)1110÷[56×(
-
)],
=1110÷[56×
-56×
],
=1110÷[24-21],
=1110÷3,
=370;
(7)36-
X=18,
36-
X+
X=18+
X,
36=18+
X,
36-18=18+
X-18,
X÷
=18÷
,
X=27;
(8)
:x=6,
x=
÷6,
x=
.
| 3 |
| 5 |
| 1 |
| 5 |
| 1 |
| 3 |
| 2 |
| 9 |
=
| 3 |
| 5 |
| 8 |
| 15 |
| 2 |
| 9 |
=
| 3 |
| 5 |
| 12 |
| 5 |
=
| 1 |
| 4 |
(2)
| 1 |
| 4 |
| 3 |
| 7 |
| 4 |
| 7 |
=
| 1 |
| 4 |
| 3 |
| 7 |
| 4 |
| 7 |
| 1 |
| 4 |
=
| 1 |
| 4 |
| 3 |
| 7 |
| 4 |
| 7 |
=
| 1 |
| 4 |
=
| 1 |
| 4 |
(3)4.2×102-8.4,
=4.2×102-4.2×2,
=4.2×(102-2),
=4.2×100,
=420;
(4)
| 5 |
| 6 |
| 9 |
| 20 |
| 1 |
| 5 |
=
| 5 |
| 6 |
| 11 |
| 20 |
| 1 |
| 5 |
=
| 50 |
| 33 |
| 1 |
| 5 |
=
| 10 |
| 33 |
(5)3.64÷4+4.36×25%,
=3.64×
| 1 |
| 4 |
| 1 |
| 4 |
=(3.64+4.36)×
| 1 |
| 4 |
=8×
| 1 |
| 4 |
=2;
(6)1110÷[56×(
| 3 |
| 7 |
| 3 |
| 8 |
=1110÷[56×
| 3 |
| 7 |
| 3 |
| 8 |
=1110÷[24-21],
=1110÷3,
=370;
(7)36-
| 2 |
| 3 |
36-
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
36=18+
| 2 |
| 3 |
36-18=18+
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 3 |
X=27;
(8)
| 3 |
| 8 |
x=
| 3 |
| 8 |
x=
| 1 |
| 16 |
点评:考查了运算定律与简便运算,四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算律简便计算.
练习册系列答案
相关题目