题目内容
运用简便方法计算．
×
+
×
+
×
（7
+5
）÷（
+
）
132÷132
．
| 5 |
| 6 |
| 1 |
| 13 |
| 5 |
| 9 |
| 2 |
| 13 |
| 5 |
| 18 |
| 6 |
| 13 |
（7
| 3 |
| 5 |
| 3 |
| 7 |
| 2 |
| 5 |
| 2 |
| 7 |
132÷132
| 132 |
| 133 |
考点：运算定律与简便运算
专题：运算定律及简算
分析：（1）通过数字转化，运用乘法分配律简算．
（2）通过数字转化，运用除法的运算性质简算．
（3）把带分数化成假分数，分子不必算出来，通过约分简算即可．
（2）通过数字转化，运用除法的运算性质简算．
（3）把带分数化成假分数，分子不必算出来，通过约分简算即可．
解答：
解：（1）
×
+
×
+
×
=
×
+
×
+
×
=（
+
+
）×
=
×
=
（2）（7
+5
）÷（
+
）
=[7+5+（
+
）×3]÷（
+
）×2
=[12+（
+
）×3]÷[（
+
）×2]
=12÷[（
+
）×2]+[（
+
）×3]÷[（
+
）×2]
=12÷
+
=
+
=19
（3）132÷132
=132÷
=132÷
=132×
=
| 5 |
| 6 |
| 1 |
| 13 |
| 5 |
| 9 |
| 2 |
| 13 |
| 5 |
| 18 |
| 6 |
| 13 |
=
| 5 |
| 6 |
| 1 |
| 13 |
| 10 |
| 9 |
| 1 |
| 13 |
| 5 |
| 3 |
| 1 |
| 13 |
=（
| 5 |
| 6 |
| 10 |
| 9 |
| 5 |
| 3 |
| 1 |
| 13 |
=
| 65 |
| 18 |
| 1 |
| 13 |
=
| 5 |
| 18 |
（2）（7
| 3 |
| 5 |
| 3 |
| 7 |
| 2 |
| 5 |
| 2 |
| 7 |
=[7+5+（
| 1 |
| 5 |
| 1 |
| 7 |
| 1 |
| 5 |
| 1 |
| 7 |
=[12+（
| 1 |
| 5 |
| 1 |
| 7 |
| 1 |
| 5 |
| 1 |
| 7 |
=12÷[（
| 1 |
| 5 |
| 1 |
| 7 |
| 1 |
| 5 |
| 1 |
| 7 |
| 1 |
| 5 |
| 1 |
| 7 |
=12÷
| 24 |
| 35 |
| 3 |
| 2 |
=
| 35 |
| 2 |
| 3 |
| 2 |
=19
（3）132÷132
| 132 |
| 133 |
=132÷
| 133×132+132 |
| 133 |
=132÷
| 132×134 |
| 133 |
=132×
| 133 |
| 132×134 |
=
| 133 |
| 134 |
点评：完成本题要注意分析式中数据，运用合适的简便方法计算．
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