题目内容
| 6.3×16.9÷0.9÷0.25= | 1.25×0.32×2.5= | |||||||
| 28.67×67+3.2×286.7+573.4×0.05= | 4.83×0.59+0.41×0.59-0.324×5.9= | |||||||
0.
|
分析:(1)根据乘法交换律和结合律进行计算;
(2)根据乘法交换律和结合律进行计算;
(3)根据乘法分配律进行计算;
(4)根据乘法分配律进行计算;
(5)0.
是2010+1=2011位小数,
11是2010-1+2=2011位小数,因为1×1=1,末尾数不是0,那么它们的乘积的小数位数,就是两个小数的位数和,即2011+2011=4022位小数,又因为1×11=11,那么小数部分有4022-2=4010个0.
(2)根据乘法交换律和结合律进行计算;
(3)根据乘法分配律进行计算;
(4)根据乘法分配律进行计算;
(5)0.
| ||
| 2010个0 |
| ||
| 2010个0 |
解答:解:
(1)6.3×16.9÷0.9÷0.25,
=(6.3÷0.9)×(16.9÷0.25),
=7×67.6,
=473.2;
(2)1.25×0.32×2.5,
=1.25×(0.8×0.4)×2.5,
=(1.25×0.8)×(0.4×2.5),
=1×1,
=1;
(3)28.67×67+3.2×286.7+573.4×0.05,
=286.7×6.7+3.2×286.7+286.7×2×0.05,
=286.7×6.7+3.2×286.7+286.7×0.1,
=286.7×(6.7+3.2+0.1)
=286.7×10,
=2867;
(4)4.83×0.59+0.41×0.59-0.324×5.9,
=4.83×0.59+0.41×0.59-3.24×0.59,
=(4.83+0.41-3.24)×0.59,
=2×0.59,
=1.18;
(5)0.
×
11,
=0.
.
(1)6.3×16.9÷0.9÷0.25,
=(6.3÷0.9)×(16.9÷0.25),
=7×67.6,
=473.2;
(2)1.25×0.32×2.5,
=1.25×(0.8×0.4)×2.5,
=(1.25×0.8)×(0.4×2.5),
=1×1,
=1;
(3)28.67×67+3.2×286.7+573.4×0.05,
=286.7×6.7+3.2×286.7+286.7×2×0.05,
=286.7×6.7+3.2×286.7+286.7×0.1,
=286.7×(6.7+3.2+0.1)
=286.7×10,
=2867;
(4)4.83×0.59+0.41×0.59-0.324×5.9,
=4.83×0.59+0.41×0.59-3.24×0.59,
=(4.83+0.41-3.24)×0.59,
=2×0.59,
=1.18;
(5)0.
| ||
| 2010个0 |
| ||
| 2010个0 |
=0.
| ||
| 4020个0 |
点评:四则运算,先弄清运算顺序,然后再进一步计算,能简算的要简算.
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