题目内容
| 计算下面各题,能简便计算的要简便计算. 10.15-6.25-3.75 | 1.75-(0.75+ | 9× |
| 1 | 6.48÷[(3.3-2.7)×0.9]. |
解:(1)10.15-6.25-3.75,
=10.15-(6.25+3.75),
=10.15-10,
=0.15;
(2)1.75-(0.75+
),
=1.75-0.75-0.4,
=1-0.4,
=0.6;
(3)9×
+
3,
=(9+3)×
,
=12×
,
=
;
(4)
,
=(
)+
,
=1+
,
=1
;
(5)1
÷(2.5×
),
=
(
×
),
=
2,
=
,
=
;
(6)6.48÷[(3.3-2.7)×0.9],
=6.48÷[0.6×0.9],
=6.48÷0.6÷0.9,
=10.8÷0.9,
=12.
分析:(1)(2)题利用减法的性质简算;
(3)运用乘法分配律的逆运算简算;
(4)先运用加法交换律和结合律把原式变为(
)+
,计算即可;
(5)按运算顺序进行计算,先算括号内的,再算括号外的;
(6)先按运算顺序进行计算,算出小括号内的结果,原式变为6.48÷[0.6×0.9],根据数字特点,运用除法的性质简算.
点评:在解答计算题时,要注意审题,仔细观察,抓住特点,巧妙解答.
=10.15-(6.25+3.75),
=10.15-10,
=0.15;
(2)1.75-(0.75+
=1.75-0.75-0.4,
=1-0.4,
=0.6;
(3)9×
=(9+3)×
=12×
=
(4)
=(
=1+
=1
(5)1
=
=
=
=
(6)6.48÷[(3.3-2.7)×0.9],
=6.48÷[0.6×0.9],
=6.48÷0.6÷0.9,
=10.8÷0.9,
=12.
分析:(1)(2)题利用减法的性质简算;
(3)运用乘法分配律的逆运算简算;
(4)先运用加法交换律和结合律把原式变为(
(5)按运算顺序进行计算,先算括号内的,再算括号外的;
(6)先按运算顺序进行计算,算出小括号内的结果,原式变为6.48÷[0.6×0.9],根据数字特点,运用除法的性质简算.
点评:在解答计算题时,要注意审题,仔细观察,抓住特点,巧妙解答.
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