题目内容
(1-
)×(1-
)×(1-
)×…×(1-
)= .
| 1 |
| 2×2 |
| 1 |
| 3×3 |
| 1 |
| 4×4 |
| 1 |
| 11×11 |
考点:分数的巧算
专题:计算问题(巧算速算)
分析:运用平方差公式,因为1-
=(1-
)×(1+
),1-
=(1-
)×(1+
),…,1-
=(1-
)×(1+
),求出每个括号内的数,约分计算.
| 1 |
| 2×2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3×3 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 11×11 |
| 1 |
| 11 |
| 1 |
| 11 |
解答:
解:(1-
)×(1-
)×(1-
)×…×(1-
)
=(1-
)×(1+
)×(1-
)×(1+
)×(1-
)×(1+
)×…(1-
)×(1+
)
=
×
×
×
×
×
×…×
×
=
×
=
故答案为:
.
| 1 |
| 2×2 |
| 1 |
| 3×3 |
| 1 |
| 4×4 |
| 1 |
| 11×11 |
=(1-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 11 |
| 1 |
| 11 |
=
| 1 |
| 2 |
| 3 |
| 2 |
| 2 |
| 3 |
| 4 |
| 3 |
| 3 |
| 4 |
| 5 |
| 4 |
| 9 |
| 10 |
| 11 |
| 10 |
=
| 1 |
| 2 |
| 11 |
| 10 |
=
| 11 |
| 20 |
故答案为:
| 11 |
| 20 |
点评:认真分析数据,运用运算技巧,灵活简算.
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