题目内容

递等式计算
578-405÷45×16 (46+165÷55)×83 [96-(42+36)]×19
15×[(45-15)÷3] [(325+175)÷5]÷25 33×20+560÷70.
(1)578-405÷45×16,
=578-9×16,
=578-144,
=434;

(2)(46+165÷55)×83,
=(46+3)×83,
=49×83,
=4067;

(3)[96-(42+36)]×19,
=[96-78]×19,
=18×19,
=342;

(4)15×[(45-15)÷3],
=15×[30÷3],
=15×10,
=150;

(5)[(325+175)÷5]÷25,
=[500÷5]÷25,
=100÷25,
=4;

(6)33×20+560÷70,
=660+8,
=668.
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