题目内容
| 用递等式计算.(怎样算简便就怎样算) 5020-2940÷28×37 |
| 3×(
| ||||||||||||||||
| 1-
| (0.25+
|
(1)5020-2940÷28×37,
=5020-105×37,
=5020-3885,
=1135;
(2)
×0.25+
×
,
=
×(
+
),
=
×1,
=
;
(3)3×(
+
-
),
=3×(
-
),
=3×
,
=2
;
(4)
÷(
-
)×3,
=
÷
×3,
=7×3,
=21;
(5)1-
×(0.32+
),
=1-
×1.92,
=1-0.24,
=0.76;
(6)(0.25+
)+(
-
),
=
+
,
=1.1.
=5020-105×37,
=5020-3885,
=1135;
(2)
| 5 |
| 6 |
| 1 |
| 4 |
| 1 |
| 6 |
=
| 1 |
| 4 |
| 5 |
| 6 |
| 1 |
| 6 |
=
| 1 |
| 4 |
=
| 1 |
| 4 |
(3)3×(
| 7 |
| 12 |
| 5 |
| 9 |
| 1 |
| 4 |
=3×(
| 41 |
| 36 |
| 1 |
| 4 |
=3×
| 32 |
| 36 |
=2
| 2 |
| 3 |
(4)
| 7 |
| 2 |
| 7 |
| 6 |
| 2 |
| 3 |
=
| 7 |
| 2 |
| 1 |
| 2 |
=7×3,
=21;
(5)1-
| 1 |
| 8 |
| 8 |
| 5 |
=1-
| 1 |
| 8 |
=1-0.24,
=0.76;
(6)(0.25+
| 7 |
| 12 |
| 14 |
| 15 |
| 2 |
| 3 |
=
| 10 |
| 12 |
| 4 |
| 15 |
=1.1.
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