题目内容

用递等式计算.(怎样算简便就怎样算)
5020-2940÷28×37
5
6
×0.25+
1
4
×
1
6
3×(
7
12
+
5
9
-
1
4
7
2
÷(
7
6
-
2
3
)×3
1-
1
8
×(0.32+
8
5
(0.25+
7
12
)+(
14
15
-
2
3
(1)5020-2940÷28×37,
=5020-105×37,
=5020-3885,
=1135;

(2)
5
6
×0.25+
1
4
×
1
6

=
1
4
×(
5
6
+
1
6
),
=
1
4
×1,
=
1
4


(3)3×(
7
12
+
5
9
-
1
4
),
=3×(
41
36
-
1
4
),
=3×
32
36

=2
2
3


(4)
7
2
÷(
7
6
-
2
3
)×3,
=
7
2
÷
1
2
×3,
=7×3,
=21;

(5)1-
1
8
×(0.32+
8
5
),
=1-
1
8
×1.92,
=1-0.24,
=0.76;

(6)(0.25+
7
12
)+(
14
15
-
2
3
),
=
10
12
+
4
15

=1.1.
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