题目内容
用递等式计算
①3÷
-
÷3
②
÷[
×(
+
)]
③(
-
+
)×12
④5.7-(1.9-1.3)
①3÷
| 3 |
| 7 |
| 3 |
| 7 |
②
| 9 |
| 20 |
| 1 |
| 2 |
| 2 |
| 3 |
| 4 |
| 5 |
③(
| 1 |
| 3 |
| 1 |
| 6 |
| 1 |
| 4 |
④5.7-(1.9-1.3)
①3÷
-
÷3,
=7-
,
=6
;
②
÷[
×(
+
)],
=
÷[
×
],
=
÷
,
=
;
③(
-
+
)×12,
=12×
-
×12+
×12,
=4-2+3,
=5;
④5.7-(1.9-1.3),
=5.7-0.6,
=5.1.
| 3 |
| 7 |
| 3 |
| 7 |
=7-
| 1 |
| 7 |
=6
| 6 |
| 7 |
②
| 9 |
| 20 |
| 1 |
| 2 |
| 2 |
| 3 |
| 4 |
| 5 |
=
| 9 |
| 20 |
| 1 |
| 2 |
| 22 |
| 15 |
=
| 9 |
| 20 |
| 11 |
| 15 |
=
| 27 |
| 44 |
③(
| 1 |
| 3 |
| 1 |
| 6 |
| 1 |
| 4 |
=12×
| 1 |
| 3 |
| 1 |
| 6 |
| 1 |
| 4 |
=4-2+3,
=5;
④5.7-(1.9-1.3),
=5.7-0.6,
=5.1.
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