题目内容
用递等式计算
2108+540÷18×24
1
×(5÷
-
÷5)
4
÷〔2.5-0.4×(2
-1.085)〕
〔1-(4
-1.75×2)〕÷2
.
解:2108+540÷18×24
=2108+30×24,
=2108+720,
=2828;
1
×(5÷
-
÷5)
=
×(5×
-
),
=
×(6-
),
=
×
,
=10;
÷(2.5-0.4)×(2
-1.085),
=4.2÷2.1×1.715,
=2×1.715,
=3.43;
[1-(
1.75×2)]
,
=[1-(
2)]
,
=[1-(
)]×
,
=[1-
]×
,
=
,
=
.
分析:本题根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的.
点评:在完成有关于分数的四则混合运算要细心,注意通分约分.
=2108+30×24,
=2108+720,
=2828;
1
=
=
=
=10;
=4.2÷2.1×1.715,
=2×1.715,
=3.43;
[1-(
=[1-(
=[1-(
=[1-
=
=
分析:本题根据四则混合运算的运算顺序计算即可:先算乘除,再算加减,有括号的要先算括号里面的.
点评:在完成有关于分数的四则混合运算要细心,注意通分约分.
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