题目内容
解方程或解比例
X:
=
:
=
.
X:
| 2 |
| 5 |
| 1 |
| 2 |
| 3 |
| 10 |
|
| x |
| 0.75 |
| 14 | ||
|
分析:(1)先根据比例的性质改写成
X=
×
,再根据等式的性质,两边同乘
即可;
(2)把50%化成0.5,根据等式的性质,两边同减去0.5,再同乘
即可;
(3)先根据比例的性质改写成
X=0.75×14,再根据等式的性质,两边同乘
即可.
| 3 |
| 10 |
| 2 |
| 5 |
| 1 |
| 2 |
| 10 |
| 3 |
(2)把50%化成0.5,根据等式的性质,两边同减去0.5,再同乘
| 3 |
| 2 |
(3)先根据比例的性质改写成
| 7 |
| 8 |
| 8 |
| 7 |
解答:解:(1)X:
=
:
,
X=
×
,
X=
,
X×
=
×
,
X=
;
(2)
X+50%=42,
X+
=42,
X+
-
=42-
,
X=41
,
X×
=
×
,
X=
;
(3)
=
,
X=0.75×14,
X×
=0.75×14×
,
X=12.
| 2 |
| 5 |
| 1 |
| 2 |
| 3 |
| 10 |
| 3 |
| 10 |
| 2 |
| 5 |
| 1 |
| 2 |
| 3 |
| 10 |
| 1 |
| 5 |
| 3 |
| 10 |
| 10 |
| 3 |
| 1 |
| 5 |
| 10 |
| 3 |
X=
| 2 |
| 3 |
(2)
| 2 |
| 3 |
| 2 |
| 3 |
| 1 |
| 2 |
| 2 |
| 3 |
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 2 |
| 2 |
| 3 |
| 1 |
| 2 |
| 2 |
| 3 |
| 3 |
| 2 |
| 83 |
| 2 |
| 3 |
| 2 |
X=
| 249 |
| 4 |
(3)
| X |
| 0.75 |
| 14 | ||
|
| 7 |
| 8 |
| 7 |
| 8 |
| 8 |
| 7 |
| 8 |
| 7 |
X=12.
点评:此题考查了根据等式的性质解方程,即等式两边同加、同减、同乘或同除以一个数(0除外),等式的左右两边仍相等;注意等号上下要对齐.
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