题目内容
(2011?新邵县)解方程
|
|
分析:(1)等式的两边同时乘14,然后等式的两边同时除以
即可;
(2)先计算
x-
x=
x,然后等式的两边同时除以
即可.
| 7 |
| 4 |
(2)先计算
| 3 |
| 4 |
| 1 |
| 5 |
| 11 |
| 20 |
| 11 |
| 20 |
解答:解:
(1)
x÷14=
,
x÷14×14=
×14,
x=7,
x÷
=7÷
,
x=4;
(2)
x-
x=
,
x=
,
x÷
=
÷
,
x=
.
(1)
| 7 |
| 4 |
| 1 |
| 2 |
| 7 |
| 4 |
| 1 |
| 2 |
| 7 |
| 4 |
| 7 |
| 4 |
| 7 |
| 4 |
| 7 |
| 4 |
x=4;
(2)
| 3 |
| 4 |
| 1 |
| 5 |
| 11 |
| 12 |
| 11 |
| 20 |
| 11 |
| 12 |
| 11 |
| 20 |
| 11 |
| 20 |
| 11 |
| 12 |
| 11 |
| 20 |
x=
| 5 |
| 3 |
点评:本题主要考查解方程,根据等式的性质进行解答即可.
练习册系列答案
相关题目