题目内容
脱式计算
999+99+9+3
[6.85-(0.65+0.7)]÷2.5
(
-
)÷(
×
)
(
+
)×7-
.
999+99+9+3
[6.85-(0.65+0.7)]÷2.5
(
| 4 |
| 3 |
| 3 |
| 4 |
| 5 |
| 6 |
| 7 |
| 4 |
(
| 5 |
| 7 |
| 3 |
| 13 |
| 21 |
| 13 |
考点:分数的四则混合运算
专题:运算顺序及法则
分析:(1)化3=1+1+1,再运用加法结合律解答,
(2)按照先算小括号里面的,再算中括号里面的,最后算括号外面的顺序计算解答,
(3)按照先同时计算括号里面的,再算括号外面的顺序计算解答,
(4)运用乘法分配律以及加法结合律解答.
(2)按照先算小括号里面的,再算中括号里面的,最后算括号外面的顺序计算解答,
(3)按照先同时计算括号里面的,再算括号外面的顺序计算解答,
(4)运用乘法分配律以及加法结合律解答.
解答:
解:(1)999+99+9+3
=(999+1)+(99+1)+(9+1)
=1000+100+10
=1110;
(2)[6.85-(0.65+0.7)]÷2.5
=[6.85-1.35]÷2.5
=5.5÷2.5
=2.2;
(3)(
-
)÷(
×
)
=
÷
=
;
(4)(
+
)×7-
=
×7+
×7-
=5+(
-
)
=5+0
=5.
=(999+1)+(99+1)+(9+1)
=1000+100+10
=1110;
(2)[6.85-(0.65+0.7)]÷2.5
=[6.85-1.35]÷2.5
=5.5÷2.5
=2.2;
(3)(
| 4 |
| 3 |
| 3 |
| 4 |
| 5 |
| 6 |
| 7 |
| 4 |
=
| 7 |
| 12 |
| 35 |
| 24 |
=
| 2 |
| 5 |
(4)(
| 5 |
| 7 |
| 3 |
| 13 |
| 21 |
| 13 |
=
| 5 |
| 7 |
| 3 |
| 13 |
| 21 |
| 13 |
=5+(
| 21 |
| 13 |
| 21 |
| 13 |
=5+0
=5.
点评:(1)运用简便方法正确进行计算,(2)正确运用简便方法解决问题,是本题考查知识点.
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