题目内容
计算,能简算可以简算.
235-135÷18
×153-0.6×53
(
+
)÷
+
10-
-
+
.
235-135÷18
| 3 |
| 5 |
(
| 4 |
| 5 |
| 1 |
| 4 |
| 7 |
| 3 |
| 7 |
| 10 |
10-
| 7 |
| 19 |
| 12 |
| 19 |
| 1 |
| 19 |
分析:(1)先算除法,再算减法;
(2)把分数化成小数,再运用乘法分配律简算;
(3)先算小括号里面的加法,再算括号外的除法,最后算括号外的加法;
(4)根据连续减去两个数等于减去这两个数的和简算.
(2)把分数化成小数,再运用乘法分配律简算;
(3)先算小括号里面的加法,再算括号外的除法,最后算括号外的加法;
(4)根据连续减去两个数等于减去这两个数的和简算.
解答:解:(1)235-135÷18,
=235-7.5,
=227.5;
(2)
×153-0.6×53,
=0.6×153-0.6×53,
=0.6×(153-53),
=0.6×100,
=60;
(3)(
+
)÷
+
,
=
×
+
,
=
+
,
=
;
(4)10-
-
+
,
=10-(
+
)+
,
=10-1+
,
=9
.
=235-7.5,
=227.5;
(2)
| 3 |
| 5 |
=0.6×153-0.6×53,
=0.6×(153-53),
=0.6×100,
=60;
(3)(
| 4 |
| 5 |
| 1 |
| 4 |
| 7 |
| 3 |
| 7 |
| 10 |
=
| 21 |
| 20 |
| 3 |
| 7 |
| 7 |
| 10 |
=
| 9 |
| 20 |
| 14 |
| 20 |
=
| 23 |
| 20 |
(4)10-
| 7 |
| 19 |
| 12 |
| 19 |
| 1 |
| 19 |
=10-(
| 7 |
| 19 |
| 12 |
| 19 |
| 1 |
| 19 |
=10-1+
| 1 |
| 19 |
=9
| 1 |
| 19 |
点评:此题是考查四则混合运算,要仔细观察算式的特点,灵活运用一些定律进行简便计算.
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