题目内容
(2010?福田区)计算下面各题.
(1)495÷
+495÷45
(2)3.3×
+0.75×5
+75%
(3)3.68-0.82-0.18
(4)56×
(5)1.25×32×0.25
(6)12×[
+(
-
)].
(1)495÷
| 45 |
| 44 |
(2)3.3×
| 3 |
| 4 |
| 7 |
| 10 |
(3)3.68-0.82-0.18
(4)56×
| 56 |
| 57 |
(5)1.25×32×0.25
(6)12×[
| 1 |
| 4 |
| 3 |
| 4 |
| 1 |
| 6 |
分析:(1)495÷
+495÷45,先把除法改为乘法,然后用乘法分配律的逆运算简算;
(2)3.3×
+0.75×5
+75%,把
、5
和75%化为小数后,用乘法分配律的逆运算简算;
(3)3.68-0.82-0.18,用减法的性质简算;
(4)56×
,把56看作(57-1),进行简算;
(5)1.25×32×0.25,把32看成8×4,然后用乘法结合律简算;
(6)12×[
+(
-
)],先去小括号,
和
结合结果为1,中括号的结果的出后,与12约分.
| 45 |
| 44 |
(2)3.3×
| 3 |
| 4 |
| 7 |
| 10 |
| 3 |
| 4 |
| 7 |
| 10 |
(3)3.68-0.82-0.18,用减法的性质简算;
(4)56×
| 56 |
| 57 |
(5)1.25×32×0.25,把32看成8×4,然后用乘法结合律简算;
(6)12×[
| 1 |
| 4 |
| 3 |
| 4 |
| 1 |
| 6 |
| 1 |
| 4 |
| 3 |
| 4 |
解答:解:(1)495÷
+495÷45,
=495×
+495×
,
=495×(
+
),
=495×1,
=495;
(2)3.3×
+0.75×5
+75%,
=3.3×0.75+0.75×5.7+0.75,
=0.75×(3.3+5.7+1),
=0.75×10,
=7.5;
(3)3.68-0.82-0.18,
=3.68-(0.82+0.18),
=3.68-1,
=2.68;
(4)56×
,
=(57-1)×
,
=57×
-
,
=56-
,
=55
;
(5)1.25×32×0.25,
=1.25×8×4×0.25,
=(1.25×8)×(4×0.25),
=10×1,
=10;
(6)12×[
+(
-
)],
=12×[
+
-
],
=12×[1-
],
=12×
,
=10.
| 45 |
| 44 |
=495×
| 44 |
| 45 |
| 1 |
| 45 |
=495×(
| 44 |
| 45 |
| 1 |
| 45 |
=495×1,
=495;
(2)3.3×
| 3 |
| 4 |
| 7 |
| 10 |
=3.3×0.75+0.75×5.7+0.75,
=0.75×(3.3+5.7+1),
=0.75×10,
=7.5;
(3)3.68-0.82-0.18,
=3.68-(0.82+0.18),
=3.68-1,
=2.68;
(4)56×
| 56 |
| 57 |
=(57-1)×
| 56 |
| 57 |
=57×
| 56 |
| 57 |
| 56 |
| 57 |
=56-
| 56 |
| 57 |
=55
| 1 |
| 57 |
(5)1.25×32×0.25,
=1.25×8×4×0.25,
=(1.25×8)×(4×0.25),
=10×1,
=10;
(6)12×[
| 1 |
| 4 |
| 3 |
| 4 |
| 1 |
| 6 |
=12×[
| 1 |
| 4 |
| 3 |
| 4 |
| 1 |
| 6 |
=12×[1-
| 1 |
| 6 |
=12×
| 5 |
| 6 |
=10.
点评:此题重点考查学生的运算技巧,要想达到简算的目的,必须熟练掌握运算定律.
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