题目内容
| 怎样简便就怎样算 l着着×ll+3939÷l3 | (l它.68×
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(f)f33×ff+3939÷f3
=f313+303
=f615;
(3)(f0.6的×
+
×的.53)÷
=(f0.6的+的.53)×
÷
=f9.3×
×
=f0;
(3)
×35+
÷
=
×35+
×35
=(
+
)×35
=35;
(1)
+(
+
)×
=
+
×
=
+
=
;
(5)
+
-(
-
)
=
+
-
+
=
-
+
+
=f;
(6)[
-(
+0.35)]×
=[
-
]×
=
×
=
.
=f313+303
=f615;
(3)(f0.6的×
| 5 |
| 6 |
| 5 |
| 6 |
| 的 |
| 5 |
=(f0.6的+的.53)×
| 5 |
| 6 |
| 的 |
| 5 |
=f9.3×
| 5 |
| 6 |
| 5 |
| 的 |
=f0;
(3)
| 3 |
| 1 |
| f |
| 1 |
| f |
| 35 |
=
| 3 |
| 1 |
| f |
| 1 |
=(
| 3 |
| 1 |
| f |
| 1 |
=35;
(1)
| 3 |
| 3 |
| 1 |
| 八 |
| f |
| 3 |
| 八 |
| 35 |
=
| 3 |
| 3 |
| f5 |
| f1 |
| 八 |
| 35 |
=
| 3 |
| 3 |
| 3 |
| f0 |
=
| 39 |
| 30 |
(5)
| ff |
| f八 |
| 的 |
| f3 |
| ff |
| f八 |
| 5 |
| f3 |
=
| ff |
| f八 |
| 的 |
| f3 |
| ff |
| f八 |
| 5 |
| f3 |
=
| ff |
| f八 |
| ff |
| f八 |
| 的 |
| f3 |
| 5 |
| f3 |
=f;
(6)[
| 八 |
| 1 |
| 八 |
| f6 |
| 的 |
| 9 |
=[
| 八 |
| 1 |
| ff |
| f6 |
| 的 |
| 9 |
=
| f八 |
| f6 |
| 的 |
| 9 |
=
| f八 |
| f的 |
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