题目内容
用递等式计算
1000-71×8
(1800-800)×4
(639-71×9)÷167
(10800-800×4)÷4.
1000-71×8
(1800-800)×4
(639-71×9)÷167
(10800-800×4)÷4.
考点:整数四则混合运算
专题:运算顺序及法则
分析:(1)先算乘法,再算减法;
(2)先算减法,再算乘法;
(3)(4)先算乘法,再算减法,最后算除法.
(2)先算减法,再算乘法;
(3)(4)先算乘法,再算减法,最后算除法.
解答:
解:(1)1000-71×8
=1000-568
=432;
(2)(1800-800)×4
=1000×4
=4000;
(3)(639-71×9)÷167
=(639-639)÷167
=0÷167
=0;
(4)(10800-800×4)÷4
=(10800-3200)÷4
=7600÷4
=1900.
=1000-568
=432;
(2)(1800-800)×4
=1000×4
=4000;
(3)(639-71×9)÷167
=(639-639)÷167
=0÷167
=0;
(4)(10800-800×4)÷4
=(10800-3200)÷4
=7600÷4
=1900.
点评:整数混合运算的关键是抓住运算顺序,正确按运算顺序计算即可.
练习册系列答案
相关题目