题目内容
脱式计算
| 4.2÷1.5-1.5×0.6 | [1-(
| (
| ||||||||||||||||||||||||
(
|
| [1
|
考点:分数的四则混合运算,小数四则混合运算
专题:运算顺序及法则
分析:①先算除法和乘法,再算减法.
②先算小括号内的减法,再算中括号内的减法,最后算括号外的乘法.
③先算括号内的减法,再算括号外的除法.
④运用减法的性质以及加法交换律与结合律简算.
⑤把除法变为乘法,约分计算.
⑥先算小括号内的减法,再算中括号内的乘法,然后算中括号内的加法,最后算括号外的除法.
②先算小括号内的减法,再算中括号内的减法,最后算括号外的乘法.
③先算括号内的减法,再算括号外的除法.
④运用减法的性质以及加法交换律与结合律简算.
⑤把除法变为乘法,约分计算.
⑥先算小括号内的减法,再算中括号内的乘法,然后算中括号内的加法,最后算括号外的除法.
解答:
解:(1)4.2÷1.5-1.5×0.6
=2.8-0.9
=1.9
(2)[1-(
-
)]×
=[1-
]×
=
×
=
(3)(
-
)÷
=
×
=
(4)(
-
)-(
-
)
=
-
-
+
=(
+
)-(
+
)
=1-1
0
(5)
×
÷
=
×
×
=
(6)[1
×(1
-
)+5
]÷3
=[
×
+5
]×
=[1+5
]×
=
×
=
=2.8-0.9
=1.9
(2)[1-(
| 1 |
| 2 |
| 1 |
| 4 |
| 2 |
| 3 |
=[1-
| 1 |
| 4 |
| 2 |
| 3 |
=
| 3 |
| 4 |
| 2 |
| 3 |
=
| 1 |
| 2 |
(3)(
| 1 |
| 2 |
| 3 |
| 8 |
| 3 |
| 4 |
=
| 1 |
| 8 |
| 4 |
| 3 |
=
| 1 |
| 6 |
(4)(
| 5 |
| 12 |
| 3 |
| 5 |
| 2 |
| 5 |
| 7 |
| 12 |
=
| 5 |
| 12 |
| 3 |
| 5 |
| 2 |
| 5 |
| 7 |
| 12 |
=(
| 5 |
| 12 |
| 7 |
| 12 |
| 3 |
| 5 |
| 2 |
| 5 |
=1-1
0
(5)
| 4 |
| 9 |
| 1 |
| 5 |
| 4 |
| 5 |
=
| 4 |
| 9 |
| 1 |
| 5 |
| 5 |
| 4 |
=
| 1 |
| 9 |
(6)[1
| 1 |
| 5 |
| 1 |
| 2 |
| 2 |
| 3 |
| 3 |
| 5 |
| 1 |
| 7 |
=[
| 6 |
| 5 |
| 5 |
| 6 |
| 3 |
| 5 |
| 7 |
| 22 |
=[1+5
| 3 |
| 5 |
| 7 |
| 22 |
=
| 33 |
| 5 |
| 7 |
| 22 |
=
| 21 |
| 10 |
点评:此题考查了小数、分数的四则混合运算,注意运算顺序和运算法则,灵活运用所学的运算定律简便计算.
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