题目内容
用递等式计算.(能简算的要简算)
(1)(32×106-352)÷38
(2)
(3)
(4)
(5)
(6)
.
解:
(1)(32×106-352)÷38,
=(3392-352)÷38,
=3040÷38,
=80;
(2)
,
=(
)×
,
=1×
,
=
;
(3)
,
=
×
,
=
;
(4)
,
=
×
-
,
=
-
,
=
;
(5)
,
=(4
+5
)+(5.375+2
),
=10+8,
=18;
(6)
,
=7.8÷[32×
+3.6],
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
分析:(1)先算乘法,再算减法,最后算除法;
(2)根据乘法分配律进行计算;
(3)先算减法和加法,再算乘法;
(4)先算加法,再算乘法,最后算减法;
(5)根据加法交换律和结合律进行计算;
(6)先算减法,再算乘法,再算加法,最后算除法.
点评:此题主要考查整数、分数、小数的四则混合运算的运算顺序和应用运算定律进行简便计算.
(1)(32×106-352)÷38,
=(3392-352)÷38,
=3040÷38,
=80;
(2)
=(
=1×
=
(3)
=
=
(4)
=
=
=
(5)
=(4
=10+8,
=18;
(6)
=7.8÷[32×
=7.8÷[12+3.6],
=7.8÷15.6,
=0.5.
分析:(1)先算乘法,再算减法,最后算除法;
(2)根据乘法分配律进行计算;
(3)先算减法和加法,再算乘法;
(4)先算加法,再算乘法,最后算减法;
(5)根据加法交换律和结合律进行计算;
(6)先算减法,再算乘法,再算加法,最后算除法.
点评:此题主要考查整数、分数、小数的四则混合运算的运算顺序和应用运算定律进行简便计算.
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