题目内容
脱式计算(能简算的要简算)
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|
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8-
|
(
|
(
|
分析:(1)根据连减的性质进行计算;
(2)先算加法,再算乘法,最后算除法;
(3)根据乘法分配律进行计算;
(4)根据连减的性质进行计算;
(5)先算加法和减法,再算除法;
(6)根据乘法分配律进行计算.
(2)先算加法,再算乘法,最后算除法;
(3)根据乘法分配律进行计算;
(4)根据连减的性质进行计算;
(5)先算加法和减法,再算除法;
(6)根据乘法分配律进行计算.
解答:解:(1)
×(1-
-
),
=
×[1-(
+
)],
=
×[1-
],
=
×
,
=
;
(2)
÷[
×(
+
)],
=
÷[
×
],
=
÷
,
=2;
(3)
÷6+
×
,
=
×
+
×
,
=(
+
)×
,
=1×
,
=
;
(4)8-
-
,
=8-(
+
),
=8-1,
=7;
(5)(
+
)÷(
-
),
=
÷
,
=
;
(6)(
+
-
)×12,
=
×12+
×12-
×12,
=10+9-6,
=19-6,
=13.
| 2 |
| 3 |
| 1 |
| 8 |
| 5 |
| 8 |
=
| 2 |
| 3 |
| 1 |
| 8 |
| 5 |
| 8 |
=
| 2 |
| 3 |
| 1 |
| 4 |
=
| 2 |
| 3 |
| 3 |
| 4 |
=
| 1 |
| 2 |
(2)
| 4 |
| 7 |
| 1 |
| 2 |
| 1 |
| 7 |
| 3 |
| 7 |
=
| 4 |
| 7 |
| 1 |
| 2 |
| 4 |
| 7 |
=
| 4 |
| 7 |
| 2 |
| 7 |
=2;
(3)
| 4 |
| 7 |
| 3 |
| 7 |
| 1 |
| 6 |
=
| 4 |
| 7 |
| 1 |
| 6 |
| 3 |
| 7 |
| 1 |
| 6 |
=(
| 4 |
| 7 |
| 3 |
| 7 |
| 1 |
| 6 |
=1×
| 1 |
| 6 |
=
| 1 |
| 6 |
(4)8-
| 6 |
| 13 |
| 7 |
| 13 |
=8-(
| 6 |
| 13 |
| 7 |
| 13 |
=8-1,
=7;
(5)(
| 5 |
| 6 |
| 3 |
| 8 |
| 5 |
| 6 |
| 3 |
| 8 |
=
| 29 |
| 24 |
| 11 |
| 24 |
=
| 29 |
| 11 |
(6)(
| 5 |
| 6 |
| 3 |
| 4 |
| 1 |
| 2 |
=
| 5 |
| 6 |
| 3 |
| 4 |
| 1 |
| 2 |
=10+9-6,
=19-6,
=13.
点评:四则运算,先弄清运算顺序,然后再进行计算即可,能简算的要简算.
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