题目内容
解方程:
=
+1.
| x |
| 16 |
| x-2 |
| 8 |
分析:依据等式的性质,方程两边同时乘16,再运用乘法分配律把方程右边化简,然后方程两边同时减12,最后同时减2x求解.
解答:解:
=
+1,
×16=(
+1)×16,
x=(x-2)×2+1×16,
x=2x-4+16,
x=2x+12,
x-12=2x+12-12,
x-12-x=2x-x,
x=-12.
| x |
| 16 |
| x-2 |
| 8 |
| x |
| 16 |
| x-2 |
| 8 |
x=(x-2)×2+1×16,
x=2x-4+16,
x=2x+12,
x-12=2x+12-12,
x-12-x=2x-x,
x=-12.
点评:解答此题的依据是等式的性质,解答的关键是把等式的右边运用乘法分配律化简,注意等号要对齐.
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