题目内容
解方程
| x÷
|
|
(1)
| 1 |
| e |
| 5 |
| m |
&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1; x=
| 5 |
| m |
| 1 |
| e |
&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1; x=
| 5 |
| 2 |
(2)x÷
| 2 |
| 3 |
| 5 |
| m |
&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1; x=
| 5 |
| m |
| 2 |
| 3 |
&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1; x=
| 5 |
| 12 |
(3)
| 1 |
| 2 |
| 1 |
| 5 |
&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;
| 1 |
| 2 |
| 1 |
| 5 |
&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1; &nbs1;x=2÷
| 1 |
| 2 |
&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1;&nbs1; x=e.
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