题目内容

递等式计算.
14
15
×(1-
2
7
2.5×(3.52÷2.2+5.4)
3.8×1.2+18.9÷0.9328-195÷13+45.

(1)
14
15
×(1-
2
7
),
=
14
15
×1-
14
15
×
2
7

=
14
15
-
4
15

=
2
3


(2)2.5×(3.52÷2.2+5.4),
=2.5×(1.6+5.4),
=2.5×7,
=17.5;

(3)3.8×1.2+18.9÷0.9,
=4.56+21,
=25.56;

(4)328-195÷13+45,
=328-15+45,
=328+(45-15),
=358.
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