题目内容
计算:
(1)11
÷[(7.35-5
)÷1.02]+82.5;
(2)(1000-195.2)÷(73.4+7.08);
(3)
×(1÷
-
÷1)+1
;
(4)(1
-
-0.5×1
)÷
;
(5)[5
+(3
-1
)÷1.75]×0.25.
(1)11
| 1 |
| 9 |
| 1 |
| 12 |
(2)(1000-195.2)÷(73.4+7.08);
(3)
| 2 |
| 7 |
| 3 |
| 4 |
| 3 |
| 4 |
| 5 |
| 6 |
(4)(1
| 1 |
| 22 |
| 1 |
| 8 |
| 3 |
| 4 |
| 10 |
| 11 |
(5)[5
| 1 |
| 24 |
| 5 |
| 8 |
| 5 |
| 12 |
考点:整数、分数、小数、百分数四则混合运算
专题:运算顺序及法则
分析:(1)先算减法,再算中括号里面的除法,再算括号外面的除法,最后算加法;
(2)先算减法和加法,再算除法;
(3)先算除法,再算减法,再算乘法,最后算加法;
(4)先算乘法,再根据减法的性质计算小括号里面的,最后算除法;
(5)先算减法,再算除法,再算加法,最后算乘法.
(2)先算减法和加法,再算除法;
(3)先算除法,再算减法,再算乘法,最后算加法;
(4)先算乘法,再根据减法的性质计算小括号里面的,最后算除法;
(5)先算减法,再算除法,再算加法,最后算乘法.
解答:
解:(1)11
÷[(7.35-5
)÷1.02]+82.5
=11
÷[2
÷1.02]+82.5
=11
÷
+82.5
=5+82.5
=87.5;
(2)(1000-195.2)÷(73.4+7.08)
=804.8÷80.48
=10;
(3)
×(1÷
-
÷1)+1
=
×(
-
)+1
=
×
+1
=
+1
=2;
(4)(1
-
-0.5×1
)÷
=(1
-
-
)÷
=[1
-(
+
)]÷
=[1
-1]÷
=
÷
=
;
(5)[5
+(3
-1
)÷1.75]×0.25
=[5
+2
÷1.75]×0.25
=[5
+
]×0.25
=6
×0.25
=1
.
| 1 |
| 9 |
| 1 |
| 12 |
=11
| 1 |
| 9 |
| 4 |
| 15 |
=11
| 1 |
| 9 |
| 20 |
| 9 |
=5+82.5
=87.5;
(2)(1000-195.2)÷(73.4+7.08)
=804.8÷80.48
=10;
(3)
| 2 |
| 7 |
| 3 |
| 4 |
| 3 |
| 4 |
| 5 |
| 6 |
=
| 2 |
| 7 |
| 4 |
| 3 |
| 3 |
| 4 |
| 5 |
| 6 |
=
| 2 |
| 7 |
| 7 |
| 12 |
| 5 |
| 6 |
=
| 1 |
| 6 |
| 5 |
| 6 |
=2;
(4)(1
| 1 |
| 22 |
| 1 |
| 8 |
| 3 |
| 4 |
| 10 |
| 11 |
=(1
| 1 |
| 22 |
| 1 |
| 8 |
| 7 |
| 8 |
| 10 |
| 11 |
=[1
| 1 |
| 22 |
| 1 |
| 8 |
| 7 |
| 8 |
| 10 |
| 11 |
=[1
| 1 |
| 22 |
| 10 |
| 11 |
=
| 1 |
| 22 |
| 10 |
| 11 |
=
| 1 |
| 20 |
(5)[5
| 1 |
| 24 |
| 5 |
| 8 |
| 5 |
| 12 |
=[5
| 1 |
| 24 |
| 5 |
| 24 |
=[5
| 1 |
| 24 |
| 53 |
| 42 |
=6
| 51 |
| 168 |
=1
| 387 |
| 672 |
点评:考查了运算定律与简便运算,四则混合运算.注意运算顺序和运算法则,灵活运用所学的运算定律简便计算.
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