题目内容
简便计算.
2.5×1.25×32
÷
-
×
×13+
×7.
2.5×1.25×32
| 13 |
| 6 |
| 7 |
| 5 |
| 1 |
| 6 |
| 5 |
| 7 |
| 7 |
| 12 |
| 11 |
| 12 |
分析:(1)根据数字特点,把32拆成4×8,运用乘法交换律和结合律简算;
(2)先把除法改为乘法,然后运用乘法分配律的逆运算简算;
(3)此题应先通过转化,把
×7化为
×11,然后运用乘法分配律的逆运算简算.
(2)先把除法改为乘法,然后运用乘法分配律的逆运算简算;
(3)此题应先通过转化,把
| 11 |
| 12 |
| 7 |
| 12 |
解答:解:(1)2.5×1.25×32,
=2.5×1.25×4×8,
=2.5×4×(125×8),
=10×1000,
=10000;
(2)
÷
-
×
,
=
×
-
×
,
=(
-
)×
,
=2×
,
=
;
(3)
× 13+
× 7,
=
×13+
×11,
=(13+11)×
,
=24×
,
=14.
=2.5×1.25×4×8,
=2.5×4×(125×8),
=10×1000,
=10000;
(2)
| 13 |
| 6 |
| 7 |
| 5 |
| 1 |
| 6 |
| 5 |
| 7 |
=
| 13 |
| 6 |
| 5 |
| 7 |
| 1 |
| 6 |
| 5 |
| 7 |
=(
| 13 |
| 6 |
| 1 |
| 6 |
| 5 |
| 7 |
=2×
| 5 |
| 7 |
=
| 10 |
| 7 |
(3)
| 7 |
| 12 |
| 11 |
| 12 |
=
| 7 |
| 12 |
| 7 |
| 12 |
=(13+11)×
| 7 |
| 12 |
=24×
| 7 |
| 12 |
=14.
点评:此题重点考查学生对乘法分配律的掌握与运用,同时也考查了对有些数字的灵活处理能力.
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