题目内容
(2002?永登县)
| 正确、合理、灵活的计算,求未知数 1.25×4×0.6×0.8×2.5 |
|
4
| ||||||||||||||||||
3
|
1
|
5×0.36-0.75X=
|
分析:(1)运用乘法的结合律、交换律进行计算;
(2)(4)按照分数的四则混合运算的顺序进行计算,先算括号内部的,在计算括号外面的;
(3)本题运用乘法的分配律进行计算,使计算更加简便.
(5)解比例,根据比例的基本性质进行解答.
(6)解方程,依据等式的基本性质进行解答.
(2)(4)按照分数的四则混合运算的顺序进行计算,先算括号内部的,在计算括号外面的;
(3)本题运用乘法的分配律进行计算,使计算更加简便.
(5)解比例,根据比例的基本性质进行解答.
(6)解方程,依据等式的基本性质进行解答.
解答:解:(1)1.25×4×0.6×0.8×2.5,
=(1.25×0.8)×(2.5×4)×0.6,
=1×10×0.6,
=6;
(2)
×[2
+(
-
)÷
],
=
×[2
+(
-
)÷
],
=
×[2
+(
-
)×3],
=
×[2
+
×3],
=
×[2
+
],
=
×
,
=1;
(3)4
+4.2×7
+1
×4
,
=4.2+4.2×7
+1
×4.2,
=4.2×(1+7
+1
),
=4.2×10,
=42;
(4)3
×1
÷(4.5-0.625÷
)÷30%,
=
×
÷(4.5-
×
)×
,
=
÷(4.5-2)×
,
=
×
×
,
=(
×
)×
,
=14×
,
=
,
=5
;
(5)1
:1
=X:
,
1
x=1
×
,
1
x=
×
,
x×
=
×
×
,
x=
×(
×
),
x=
×
,
x=
;
(6)5×0.36-0.75X=
,
1.8-0.75x=0.6,
0.75x=1.2,
x×
=1.2×
,
x=1.6;
=(1.25×0.8)×(2.5×4)×0.6,
=1×10×0.6,
=6;
(2)
| 5 |
| 16 |
| 2 |
| 5 |
| 2 |
| 3 |
| 2 |
| 5 |
| 1 |
| 3 |
=
| 5 |
| 16 |
| 2 |
| 5 |
| 2 |
| 3 |
| 2 |
| 5 |
| 1 |
| 3 |
=
| 5 |
| 16 |
| 2 |
| 5 |
| 10 |
| 15 |
| 6 |
| 15 |
=
| 5 |
| 16 |
| 2 |
| 5 |
| 4 |
| 15 |
=
| 5 |
| 16 |
| 2 |
| 5 |
| 4 |
| 5 |
=
| 5 |
| 16 |
| 16 |
| 5 |
=1;
(3)4
| 1 |
| 5 |
| 5 |
| 7 |
| 2 |
| 7 |
| 1 |
| 5 |
=4.2+4.2×7
| 5 |
| 7 |
| 2 |
| 7 |
=4.2×(1+7
| 5 |
| 7 |
| 2 |
| 7 |
=4.2×10,
=42;
(4)3
| 1 |
| 2 |
| 1 |
| 5 |
| 5 |
| 16 |
=
| 7 |
| 2 |
| 6 |
| 5 |
| 5 |
| 8 |
| 16 |
| 5 |
| 10 |
| 3 |
=
| 21 |
| 5 |
| 10 |
| 3 |
=
| 21 |
| 5 |
| 2 |
| 5 |
| 10 |
| 3 |
=(
| 21 |
| 5 |
| 10 |
| 3 |
| 2 |
| 5 |
=14×
| 2 |
| 5 |
=
| 28 |
| 5 |
=5
| 3 |
| 5 |
(5)1
| 1 |
| 5 |
| 2 |
| 7 |
| 9 |
| 14 |
1
| 2 |
| 7 |
| 1 |
| 5 |
| 9 |
| 14 |
1
| 2 |
| 7 |
| 6 |
| 5 |
| 9 |
| 14 |
| 9 |
| 7 |
| 7 |
| 9 |
| 6 |
| 5 |
| 9 |
| 14 |
| 7 |
| 9 |
x=
| 6 |
| 5 |
| 9 |
| 14 |
| 7 |
| 9 |
x=
| 6 |
| 5 |
| 1 |
| 2 |
x=
| 3 |
| 5 |
(6)5×0.36-0.75X=
| 3 |
| 5 |
1.8-0.75x=0.6,
0.75x=1.2,
| 3 |
| 4 |
| 4 |
| 3 |
| 4 |
| 3 |
x=1.6;
点评:此题考查了运算定律与简便运算,四则混合运算.注意运算顺序和运算法则,灵活运用所学的运算定律进行简便计算.
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