题目内容
解下列方程.
| 4Χ-3×5=189 |
|
(1)4x-3×5=189,
4x-15+15=189+15,
4x÷4=204÷4,
x=51;
(2)
×
-
x=
,
-
x+
x=
+
x,
-
=
+
x-
,
÷
=
x÷
,
x=
.
4x-15+15=189+15,
4x÷4=204÷4,
x=51;
(2)
| 5 |
| 6 |
| 1 |
| 5 |
| 1 |
| 3 |
| 1 |
| 8 |
| 1 |
| 6 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 8 |
| 1 |
| 3 |
| 1 |
| 6 |
| 1 |
| 8 |
| 1 |
| 8 |
| 1 |
| 3 |
| 1 |
| 8 |
| 1 |
| 24 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 3 |
x=
| 1 |
| 8 |
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