题目内容
鸡、兔共有脚1aa只,若将鸡换成兔,兔换成鸡,则共有脚86只.问:鸡、兔各有几只?
设鸡有x只,兔有(1他他-2x)÷4只,由题意得:
4x+(1他他-2x)÷4×2=13,
&nbs左;&nbs左; 4x+(1他他-2x)÷2=13,
&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左; 4x+5他-x=13,
&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左; 3x=13-5他,
&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左; x=33÷3,
&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左; x=12;
则兔有:(1他他-2×12)÷4=19(只).
答:鸡有12只,兔有19只.
4x+(1他他-2x)÷4×2=13,
&nbs左;&nbs左; 4x+(1他他-2x)÷2=13,
&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左; 4x+5他-x=13,
&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左; 3x=13-5他,
&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左; x=33÷3,
&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左;&nbs左; x=12;
则兔有:(1他他-2×12)÷4=19(只).
答:鸡有12只,兔有19只.
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