题目内容
用适当的方法解答下题
| 4.85×0.17+0.485×8.3 |
|
(1)4.85×0.17+0.485×8.3,
=0.485×1.7+0.485×8.3,
=0.485×(1.7+8.3),
=0.485×10,
=4.85;
(2)
×87.5+12.5×
-4÷11,
=
×87.5+12.5×
-
,
=
×(87.5+12.5-1),
=
×99,
=36.
=0.485×1.7+0.485×8.3,
=0.485×(1.7+8.3),
=0.485×10,
=4.85;
(2)
| 4 |
| 11 |
| 4 |
| 11 |
=
| 4 |
| 11 |
| 4 |
| 11 |
| 4 |
| 11 |
=
| 4 |
| 11 |
=
| 4 |
| 11 |
=36.
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