题目内容
计算:
1997×19961996-1996×19971997
1
+2
+3
+…+10
×39+
×25+
×
(3.6×0.75×1.2)÷(1.5×24×0.18)
1997×19961996-1996×19971997
1
| 1 |
| 2 |
| 1 |
| 6 |
| 1 |
| 12 |
| 1 |
| 110 |
| 1 |
| 4 |
| 3 |
| 4 |
| 26 |
| 4 |
| 3 |
| 13 |
(3.6×0.75×1.2)÷(1.5×24×0.18)
考点:四则混合运算中的巧算,分数的巧算
专题:计算问题(巧算速算)
分析:(1)因为19961996=1996×10001,19971997=1997×10001,因此原式变为1997×1996×10001-1996×1997×10001,减号两边算式相同,故结果为0.
(2)把每个分数的整数部分与分数部分分别相加,整数部分用高斯求和公式计算,分数部分,把每个分数拆成两个分数相减的形式,通过加减相互抵消,求得结果.
(4)运用除法的运算性质建.
(2)把每个分数的整数部分与分数部分分别相加,整数部分用高斯求和公式计算,分数部分,把每个分数拆成两个分数相减的形式,通过加减相互抵消,求得结果.
(4)运用除法的运算性质建.
解答:
解:(1)解:1997×19961996-1996×19971997
=1997×1996×10001-1996×1997×10001
=0
(2)1
+2
+3
+…+10
=(1+2+3++…+10)+(
+
+
+…+
)
=(1+10)×10÷2+(1-
+
-
+
-
+
-
)
=55+(1-
)
=55+
=55
(3)
×39+
×25+
×
=
×39+
×3×25+
×26×
=
×(39+75+6)
=
×120
=30
(4)(3.6×0.75×1.2)÷(1.5×24×0.18)
=(3.6÷0.18)×(0.75÷1.5)×(1.2÷24)
=20×0.5×0.05
=10×0.05
=0.5
=1997×1996×10001-1996×1997×10001
=0
(2)1
| 1 |
| 2 |
| 1 |
| 6 |
| 1 |
| 12 |
| 1 |
| 110 |
=(1+2+3++…+10)+(
| 1 |
| 2 |
| 1 |
| 6 |
| 1 |
| 12 |
| 1 |
| 110 |
=(1+10)×10÷2+(1-
| 1 |
| 2 |
| 1 |
| 2 |
| 1 |
| 3 |
| 1 |
| 3 |
| 1 |
| 4 |
| 1 |
| 10 |
| 1 |
| 11 |
=55+(1-
| 1 |
| 11 |
=55+
| 10 |
| 11 |
=55
| 10 |
| 11 |
(3)
| 1 |
| 4 |
| 3 |
| 4 |
| 26 |
| 4 |
| 3 |
| 13 |
=
| 1 |
| 4 |
| 1 |
| 4 |
| 1 |
| 4 |
| 3 |
| 13 |
=
| 1 |
| 4 |
=
| 1 |
| 4 |
=30
(4)(3.6×0.75×1.2)÷(1.5×24×0.18)
=(3.6÷0.18)×(0.75÷1.5)×(1.2÷24)
=20×0.5×0.05
=10×0.05
=0.5
点评:要想算得快、算得巧,就要仔细观察题目中数字构成的特点和规律,运用运算定律或运算技巧,进行简便计算.
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