题目内容
找窍门,怎样算简便就怎样算.
(1)
×
-
÷
(2)4-
-
(3)3
×[(1
+
)×2
]
(4)[
-0÷(
+
)]×1
(5)20
×83+1.7×200
(6)
÷[(
-
)÷
].
(1)
| 5 |
| 6 |
| 6 |
| 5 |
| 9 |
| 10 |
| 9 |
| 5 |
(2)4-
| 5 |
| 11 |
| 7 |
| 11 |
(3)3
| 1 |
| 5 |
| 2 |
| 3 |
| 1 |
| 5 |
| 1 |
| 7 |
(4)[
| 3 |
| 4 |
| 1 |
| 7 |
| 2 |
| 13 |
| 1 |
| 3 |
(5)20
| 1 |
| 100 |
| 1 |
| 10 |
(6)
| 4 |
| 5 |
| 5 |
| 8 |
| 1 |
| 2 |
| 5 |
| 8 |
分析:算式(1)(4)可根据四则混合运算的运算顺序计算即可,即先算乘除,再算加减,有括号的要先算括号里面的.、
算式(2)可根据一个减两个数,等于减去这两个数的和的减法性质进行计算;
算式(3)(6)可将中括号中的算式根据乘法分配律进行计算.
算式(5)可先根据乘法算式的性质将20.01×83变为200.1×8.3后,再根据乘法分配律进行计算.
算式(2)可根据一个减两个数,等于减去这两个数的和的减法性质进行计算;
算式(3)(6)可将中括号中的算式根据乘法分配律进行计算.
算式(5)可先根据乘法算式的性质将20.01×83变为200.1×8.3后,再根据乘法分配律进行计算.
解答:解:(1)
×
-
÷
=1-
×
,
=1-
,
=
;
(2)4-
-
=4-(
+
),
=4-1,
=3;
(3)3
×[(1
+
)×2
]
=
×[(
+
)×
],
=
×[
×
+
×
],
=
×[
+
],
=
×4,
=12
;
(4)[
-0÷(
+
)]×1
=[
-0]×
,
=
×
,
=1;
(5)20
×83+1.7×200
=20.01×83+1.7×200.1
=200.1×8.3+1.7×200.1,
=(8.3+1.7)×200.1,
=10×200.1,
=2001;
(6)
÷[(
-
)÷
]
=
÷[(
-
)×
],
=
÷[
×
-
×
],
=
÷[1-
],
=
÷
,
=4.
| 5 |
| 6 |
| 6 |
| 5 |
| 9 |
| 10 |
| 9 |
| 5 |
=1-
| 9 |
| 10 |
| 5 |
| 9 |
=1-
| 1 |
| 2 |
=
| 1 |
| 2 |
(2)4-
| 5 |
| 11 |
| 7 |
| 11 |
=4-(
| 5 |
| 11 |
| 7 |
| 11 |
=4-1,
=3;
(3)3
| 1 |
| 5 |
| 2 |
| 3 |
| 1 |
| 5 |
| 1 |
| 7 |
=
| 16 |
| 5 |
| 5 |
| 3 |
| 1 |
| 5 |
| 15 |
| 7 |
=
| 16 |
| 5 |
| 5 |
| 3 |
| 15 |
| 7 |
| 1 |
| 5 |
| 15 |
| 7 |
=
| 16 |
| 5 |
| 25 |
| 7 |
| 3 |
| 7 |
=
| 16 |
| 5 |
=12
| 4 |
| 5 |
(4)[
| 3 |
| 4 |
| 1 |
| 7 |
| 2 |
| 13 |
| 1 |
| 3 |
=[
| 3 |
| 4 |
| 4 |
| 3 |
=
| 3 |
| 4 |
| 4 |
| 3 |
=1;
(5)20
| 1 |
| 100 |
| 1 |
| 10 |
=20.01×83+1.7×200.1
=200.1×8.3+1.7×200.1,
=(8.3+1.7)×200.1,
=10×200.1,
=2001;
(6)
| 4 |
| 5 |
| 5 |
| 8 |
| 1 |
| 2 |
| 5 |
| 8 |
=
| 4 |
| 5 |
| 5 |
| 8 |
| 1 |
| 2 |
| 8 |
| 5 |
=
| 4 |
| 5 |
| 5 |
| 8 |
| 8 |
| 5 |
| 1 |
| 2 |
| 8 |
| 5 |
=
| 4 |
| 5 |
| 4 |
| 5 |
=
| 4 |
| 5 |
| 1 |
| 5 |
=4.
点评:完成有关于分数的四则混合运算时要细心,注意通分约分.
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