题目内容
解方程
(1)2x-
x÷
=510
(2)5:(x-1)=
:18%
(1)2x-
| 3 |
| 4 |
| 4 |
| 5 |
(2)5:(x-1)=
| 3 |
| 20 |
分析:(1)先化简,再根据等式的性质,在方程两边同时乘上
求解,
(2)先根据比例的基本性质,把原式转化为
×(x-1)=5×18%,再化简,然后根据等式的性质,在方程两边同时乘上
,再加上1求解.
| 16 |
| 17 |
(2)先根据比例的基本性质,把原式转化为
| 3 |
| 20 |
| 20 |
| 3 |
解答:解:(1)2x-
x÷
=510,
2x-
x=510,
x=510,
x×
=510×
,
x=480;
(2)5:(x-1)=
:18%,
×(x-1)=5×18%,
×(x-1)×
=0.9×
,
x-1+1=6+1,
x=7.
| 3 |
| 4 |
| 4 |
| 5 |
2x-
| 15 |
| 16 |
| 17 |
| 16 |
| 17 |
| 16 |
| 16 |
| 17 |
| 16 |
| 17 |
x=480;
(2)5:(x-1)=
| 3 |
| 20 |
| 3 |
| 20 |
| 3 |
| 20 |
| 20 |
| 3 |
| 20 |
| 3 |
x-1+1=6+1,
x=7.
点评:本题考查了学生根据等式的性质和比例的基本性质解方程的能力,注意等号对齐.
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