题目内容
解方程.
| x÷
|
|
| x+
|
考点:方程的解和解方程
专题:简易方程
分析:(1)根据等式的性质,两边同乘
即可.
(2)根据等式的性质,两边同乘
即可.
(3)根据等式的性质,两边同乘
,再同乘
即可.
(4)根据等式的性质,两边同乘
即可.
(5)原式变为
x=9,根据等式的性质,两边同乘
即可.
| 8 |
| 5 |
(2)根据等式的性质,两边同乘
| 2 |
| 9 |
(3)根据等式的性质,两边同乘
| 1 |
| 6 |
| 4 |
| 3 |
(4)根据等式的性质,两边同乘
| 5 |
| 2 |
(5)原式变为
| 3 |
| 2 |
| 2 |
| 3 |
解答:
解:(1)
x=15
x×
=15×
x=24
(2)x÷
=
x÷
×
=
×
x=
(3)
x÷
=18
x÷
×
=18×
x=3
x×
=3×
x=4
(4)
x=
×
x=
x×
=
×
x=
(5)x+
x=9
x=9
x×
=9×
x=6
| 5 |
| 8 |
| 5 |
| 8 |
| 8 |
| 5 |
| 8 |
| 5 |
x=24
(2)x÷
| 2 |
| 9 |
| 6 |
| 7 |
x÷
| 2 |
| 9 |
| 2 |
| 9 |
| 6 |
| 7 |
| 2 |
| 9 |
x=
| 4 |
| 21 |
(3)
| 3 |
| 4 |
| 1 |
| 6 |
| 3 |
| 4 |
| 1 |
| 6 |
| 1 |
| 6 |
| 1 |
| 6 |
| 3 |
| 4 |
| 3 |
| 4 |
| 4 |
| 3 |
| 4 |
| 3 |
x=4
(4)
| 2 |
| 5 |
| 4 |
| 9 |
| 3 |
| 8 |
| 2 |
| 5 |
| 1 |
| 6 |
| 2 |
| 5 |
| 5 |
| 2 |
| 1 |
| 6 |
| 5 |
| 2 |
x=
| 5 |
| 12 |
(5)x+
| 1 |
| 2 |
| 3 |
| 2 |
| 3 |
| 2 |
| 2 |
| 3 |
| 2 |
| 3 |
x=6
点评:考查了根据等式的性质解方程,即等式两边同加上、同减去、同乘上或同除以一个不为0的数,等式仍相等.同时注意“=”上下要此题对齐.
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