题目内容
解方程:
x+1
=2
.
x+1
| 3 |
| 4 |
| 2 |
| 5 |
分析:等式的两边同时减去1
即可.
| 3 |
| 4 |
解答:解:根据题意可得:
x+1
=2
,
x+1
-1
=2
-1
,
x=
.
x+1
| 3 |
| 4 |
| 2 |
| 5 |
x+1
| 3 |
| 4 |
| 3 |
| 4 |
| 2 |
| 5 |
| 3 |
| 4 |
x=
| 13 |
| 20 |
点评:本题主要考查解方程,根据等式的性质进行解答即可.
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