题目内容

递等式计算
3
4
÷3-
1
10
)×(1-
1
3

3
5
-
3
4
÷3+
3
5

4
9
÷(
5
6
-
1
2
)+
5
16

[2
1
3
-(90%+
2
3
)]÷
7
5

3
4
+0.25÷(
2
3
-1.5×
1
3
(1)(
3
4
÷3-
1
10
)×(1-
1
3
),
=(
1
4
-
1
10
)×(1-
1
3
),
=
3
20
×
2
3

=
1
10


(2)
3
5
-
3
4
÷3+
3
5

=
3
5
-
1
4
+
3
5

=(
3
5
+
3
5
)-
1
4

=
6
5
-
1
4

=
19
20


(3)
4
9
÷(
5
6
-
1
2
)+
5
16

=
4
9
÷
1
3
+
5
16

=
4
3
+
5
16

=
79
48


(4)[2
1
3
-(90%+
2
3
)]÷
7
5

=[2
1
3
-
9
10
-
2
3
7
5

=[2
1
3
-
2
3
-
9
10
7
5

=[
5
3
-
9
10
]÷
7
5

=
23
30
×
5
7

=
23
42


(5)
3
4
+0.25÷(
2
3
-1.5×
1
3
),
=
3
4
+
1
4
÷(
2
3
-
3
2
×
1
3
),
=
3
4
+
1
4
÷(
2
3
-
1
2
),
=
3
4
+
1
4
÷
1
6

=
3
4
+
6
4

=
9
4
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